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kobusy [5.1K]
3 years ago
14

Find the area of the parallelogram whose vertices are given below. ​A(negative 2​,2​) ​B(2​,0​) ​C(10​,3​) ​D(6​,5​)

Mathematics
1 answer:
swat323 years ago
5 0

Answer: Area of Parallelogram is 28 units squared.

Step-by-step explanation:

Knowing, any two vector sides of a parallelogram sharing the same initial point, we can find the area of parallelogram that two vectors are shaping, using the cross product of these two vectors a×b, where the area is given by

Area= |a×b| ___ (1)

From the given points,we may choose any three of them such and find a two vector and expresses the sides of parallelogram " or one side and a diagonal of parallelogram" ,we may choose for example B ,C and D.

Moreover, we may choose point B, to be common point for the two sides " the initial point of two vector" thus we need to find vector BD and vector BC .

Calculations are given in picture.

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nadezda [96]

Answers:

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=================================================

Explanation:

The weird looking E symbol is the greek uppercase letter sigma which stands for "sum". You'll be adding everything in the x^2 column to find that 64+144+256+400 = 864, which is already done for you in the table (as the 864 is at the bottom of the second column, in the "total" row).

In short, you just copy the 864 into the first box.

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For the second box, you'll square the 56 to get 3136

This is because the table shows that adding up all the x values leads to 56

(8+12+16+20 = 56)

So that means \sum x = 56 and \left(\sum x\right)^2 = (56)^2 = 3136

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2 years ago
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