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3 years ago

16. What statement can be made about the distance between the vertices of a triangle and the circumcenter?

Mathematics

1 answer:

slamgirl [31]3 years ago

7 0

Answer:

O the circumcenter is equidistant to all three vertices

Step-by-step explanation:

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Find the midpoint of (0,4) and (-4,-12)

ankoles [38]

The answer is (-2,-4) to solve this you need to add the X’s and divide by 2 and that will be your X for the midpoint, you do the same with the Y’s to find the y for your midpoint

5 0

3 years ago

the mean average distance that jack runs in his last 10 runs is 5.7 miles. work out the distance that he would need to make this

ziro4ka [17]

Answer:

9 miles

Step-by-step explanation:

mean is calculated as

mean = $\frac{sum}{count}$ , then

$\frac{sum}{10}$ = 5.7 ( multiply both sides by 10 )

sum = 57

let x be the distance he needs to cover so mean is 6 , that is

$\frac{sum+x}{11}$ = 6 ( multiply both sides by 11 )

sum + x = 66 , that is

57 + x = 66 ( subtract 57 from both sides )

x = 9

That is he would have to run 9 miles

3 0

2 years ago

Simplify 0.5x-2y > 3

egoroff_w [7]

I will assume you want it in the form of y>mx+b

0.5x-2y>3

0.5x-3>2y

0.25x-1.5>y

4 0

3 years ago

Read 2 more answers

Evaluate the expression below if x = 3 and y= -4.<br> X - Y - 3+ (-57)

Firdavs [7]

Answer:

-53

Step-by-step explanation:

If x=3 and y=-4

Plug the numbers into the equation

3 - (-4) - 3 + (-57)

Now solve the equation right to left

3 - (-4) = 7

7 - 3 = 4

4 - 57 = -53

So the answer is -53

4 0

3 years ago

Read 2 more answers

The side length of a square ice cube is claimed to be 1.0 inches, correct to within 0.001 inch. Use linear approximation to esti

Olenka [21]

Answer:

0.012

Step-by-step explanation:

Linear approximation says that,

$f(x) \approx f(x_o)+f'(x_o)(x-x_o)$

For a cube the surface area is $6x^2$ .

So the side is 1.0 inch in, the surface area is $=6\times1^2 = 6$ square inches.

In Linear approximation means you ignore the term $x_o^2$ , if $x_o$ is a small number, because then $x_o^2$ will be a very smalle number and that does not contribute much to the error.

So the surface area is approximately,

$6x^2=6x_o^2+12x_o(x-x_o)$

So here, $x=1.001, x_o=0.001$

The error in the area is approximately,

$12 \times 0.001=0.012$

So the error is 0.012.

3 0

3 years ago