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krek1111 [17]
3 years ago
5

Does every integer have a successor?

Mathematics
2 answers:
bezimeni [28]3 years ago
8 0

Answer:

Yes every integer has a successor and a predecessor

Step-by-step explanation:

Anna11 [10]3 years ago
3 0

Answer:

Step-by-step explanation:

yes

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What is the solution set to the inequality (4x-3)(2x-1)20?
Fynjy0 [20]

The given question is wrong.

Question:

What is the solution set to the inequality (4x – 3) (2x – 1) ≥ 0?

(A) \{x| x\leq 3\ \text {or} \ x\geq 1

(B) \{x| x\leq 2\ \text {or} \ x\geq \frac{4}{3}

(C) \{x| x\leq \frac{1}{2}\ \text {or} \ x\geq \frac{3}{4}

(D) \{x| x\leq \frac{-1}{2}\ \text {or} \ x\geq \frac{-3}{4}

Answer:

The solution set to the given inequality is \{x| x\leq \frac{1}{2}\ \text {or} \ x\geq \frac{3}{4}.

Solution:

Given expression is (4x – 3) (2x – 1) ≥ 0.

Let us take the expression is equal to zero.

(4x – 3) (2x – 1) = 0

By quadratic factor, If AB = 0, then A = 0 or B = 0.

(4x – 3) = 0 or (2x – 1) = 0

Let us take the first factor equal to zero.

⇒ 4x – 3 = 0

⇒ 4x = 3

$x=\frac{3}{4}

Now, take the second factor equal to zero.

⇒ 2x – 1 = 0

⇒ 2x = 1

$x=\frac{1}{2}

So, $x=\frac{1}{2},x=\frac{3}{4}.

Now, write it in the inequality to make the statement true.

$x\geq \frac{1}{2}\ \text{(or)}\ x\leq \frac{3}{4}

Option C is the correct answer.

The solution set to the given inequality is \{x| x\leq \frac{1}{2}\ \text {or} \ x\geq \frac{3}{4}.

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If the effective rate is 10% percent and the contract rate is 8% percent, the bond will sell at
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Answer:it would be B HOPE THIS HELPS


Step-by-step explanation:


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Answer:

The answer to the question is 1

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one to one function

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