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kondor19780726 [428]

2 years ago

10

kim just went to the store and bought 2 presents that cost kim $1,800 and her Taxes or 88 cents how much does kimmlin have to pa

y?

1 answer:

strojnjashka [21]2 years ago

6 0

3384 because .88 times 1800 is 1584 and you have to add that to 1800 making it 3384 (or the questions is really easy and its just 1800.88)

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Can someone please help me on this question <br> I will give brainliest

xz_007 [3.2K]

Answer:

A) 3 in

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

<u>Geometry</u>

Surface Area of a Sphere: SA = 4πr²
Diameter: d = 2r

Step-by-step explanation:

<u>Step 1: Define</u>

SA = 23 in²

<u>Step 2: Find </u><em><u>r</u></em>

Substitute [SAS]: 23 in² = 4πr²
Isolate <em>r </em>term: 23 in²/(4π) = r²
Isolate <em>r</em>: √[23 in²/(4π)] = r
Rewrite: r = √[23 in²/(4π)]
Evaluate: r = 1.35288 in

<u>Step 3: Find </u><em><u>d</u></em>

Substitute [D]: d = 2(1.35288 in)
Multiply: d = 2.70576 in
Round: d ≈ 3 in

4 0

2 years ago

Round 1,490 to the nearest hundred

Arlecino [84]

The answer is 1,500..

3 0

3 years ago

Read 2 more answers

Example 2: Combining Use of the Multiplication and Addition Rules

bulgar [2K]

Answer:

The probability of getting 6's on both cubes is $\frac{1}{36}$ .

The probability that the total score is at least 11 is $\frac{1}{12}$ .

Step-by-step explanation:

Consider the provided information.

A red cube has faces labeled 1 through 6, and a blue cube has faces labeled in the same way.

Part (A) Both cubes show 6’s.

Probability of getting 6 on red cube is $\frac{1}{6}$

Probability of getting 6 on blue cube is $\frac{1}{6}$

Thus, the probability of getting 6's on both cubes is:

$P(\text{Both 6's})=\frac{1}{6}\times\frac{1}{6}=\frac{1}{36}$

Hence, the probability of getting 6's on both cubes is $\frac{1}{36}$ .

Part (B) The total score is at least 11.

The possible number of outcomes in which total score is at least 11 is:

Red shows 6 and Blue shows 5.

Blue shows 6 and Red shows 5.

Blue shows 6 and Red shows 6.

Thus, the probability of total score is at least 11.

$P(\text{Total is at least 11})=\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}\\P(\text{Total is at least 11})=\frac{1}{12}$

Hence, the probability that the total score is at least 11 is $\frac{1}{12}$ .

3 0

2 years ago

6(2x-11)+15=21 is it correct

Alina [70]

I got 6 for my answer, but I'm not 100% sure if I'm right.

6(2x-11)+15=21
12x-66+15=21
12x-51=21
+51 +51
12x=72
----- ----
12 12
x=6

5 0

2 years ago

Read 2 more answers

How to do 10 to 4 decrease

USPshnik [31]

If you're talking about the ratio 10:4, you can decrease it by dividing both numbers by 2.

10:4=5:2

The ratio decreases to 5:2

6 0

3 years ago

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