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kondor19780726 [428]

3 years ago

10

kim just went to the store and bought 2 presents that cost kim $1,800 and her Taxes or 88 cents how much does kimmlin have to pa

y?

1 answer:

strojnjashka [21]3 years ago

6 0

3384 because .88 times 1800 is 1584 and you have to add that to 1800 making it 3384 (or the questions is really easy and its just 1800.88)

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6 bags of plaster do 33m2 how many m2 can be done with 5 bags

pav-90 [236]

<span>6 bags of plaster do 33m2
5 bags .........................?

33 * 5 / 6 = 27.5

answer: 27.5</span><span>m2</span>

8 0

3 years ago

You draw two cards from a standard deck of 52 cards but before you draw the second card

UNO [17]

I am not understanding the question would you like a fraction????

3 0

3 years ago

Geometry help pls math

Yanka [14]

Answer:

to find the scale factor we just need to take one of the side lengths of the larger figure, 20, and divide it by the corresponding side length in the smaller figure, 8. Therefore 20/8 is correct

Step-by-step explanation:

7 0

3 years ago

Factoring help. Need step by step guidance ....<br><br> 35n ^ 2 + 22n + 3

Maksim231197 [3]

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(7n + 3)(5n + 1)
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so answer is
(7n + 3)(5n + 1)

5 0

3 years ago

The temperature at a point (x, y) is T(x, y), measured in degrees Celsius. A bug crawls so that its position after t seconds is

anastassius [24]

Answer:

The rate of change of temperature is 1.29 degree Celsius per second.

Step-by-step explanation:

We are given the following information in the question:

The temperature at a point (x, y) is T(x, y), measured in degrees Celsius where x and y are measured in centimeters.

$x = \sqrt{2+t}\\\\y = 5 + \displaystyle\frac{1}{14}t$

$T_x(4,6) = 8, T_y(4,6) = 4$

We have to find the rate at which the temperature is rising on the bug's path after 14 seconds.

At t = 14 seconds, we have,

$x = \sqrt{2+14} = 4\\\\y = 5 + \displaystyle\frac{1}{14}(14) = 5+1 = 6$

To find rate of change of temperature, we differentiate,

$\displaystyle\frac{dT}{dt} = \frac{dT}{dx}\frac{dx}{dt} + \frac{dT}{dy}\frac{dy}{dt}\\\\\displaystyle\frac{dT}{dt} = T_x(x,y)(\frac{1}{2\sqrt{2+t}}) + T_y(x,y)\frac{1}{14}\\\\At~ t = 14, x = 4, y = 6\\\\\frac{dT}{dt} = T_x(4,6)(\frac{1}{2\sqrt{2+t}}) + T_y(4,6)\frac{1}{14}\\\\\frac{dT}{dt} = 8\times \frac{1}{8} +4\times \frac{1}{14} = 1 + 0.2857 = 1.2857$

Thus, the rate of change of temperature is 1.29 degree Celsius per second.

7 0

3 years ago