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4vir4ik [10]
2 years ago
6

A school requires that 1 adult accompany every 8 students on a field trip. How many adults are needed to accompany 32 students?

Mathematics
1 answer:
mrs_skeptik [129]2 years ago
5 0

Answer: 4 adults are needed to accompany 32 students.

Step-by-step explanation:

Given: School requires 1 adult to accompany every 8 students on a field trip.

The number of adults are needed to accompany 32 students = \dfrac{32}{\text{Number of students accompanied by an adult}}

=\dfrac{32}{8}\\\\=4

Hence, 4 adults are needed to accompany 32 students.

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The measures of the angles of a triangle are shown in the figure below. Solve for x.
morpeh [17]

Answer:

63

Step-by-step explanation:

40+77=117

180-117=63

3 0
3 years ago
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Solve for x: one over four (4x + 15) = 24
Komok [63]

Answer:

x = 81/4

Step-by-step explanation:

multiply both sides by 4

4x + 15 = 96

subtract 15 from both sides

4x = 81

divide both sides by 4

x= 81/4

i hope that's right

8 0
3 years ago
What is the anwser to 3(2t+5)=5t+25
Elena L [17]

3(2t+5)=5t+25

Multiply the bracket with 3

(3)(2t)(3)(5)=5t+25

6t+15=5t+25

Move 5t to the other side. Sign changes from +5t to -5t

6t-5t+15=5t-5t+25

6t-5t+15=25

Move +15 to the other side. Sign changes from +15 to -15

6t-5t+15-15=25-15

6t-5t=10

1t=10

divide by 1

1/1t=10/t

t=10

Answer: t=10

6 0
3 years ago
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The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 101010 denarii per day to support 444
givi [52]

<u>the correct question is</u>

The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?

Let

x-------> the cost to support a legionary per day

y-------> the cost to support an archer per day

we know that

4x+4y=10 ---------> equation 1

2x+2y=5 ---------> equation 2

If you multiply equation 1 by 2

2*(2x+2y)=2*5-----------> 4x+4y=10

so

equation 1 and equation 2 are the same

The system has infinite solutions-------> Is a consistent dependent system

therefore

<u>the answer is</u>

We cannot solve for a unique cost for each soldier, because there are infinite solutions.

5 0
3 years ago
The question is below:
SSSSS [86.1K]

Answer:

Triangles ABE and CDE are congruent by AAS.

Step-by-step explanation:

AB ≅ DC   (Opposite sides of a parallelogram are congruent.

m < AEB = m < DEC     (Vertical angles).

m < ABE = m < EDC     ( Alternate Interior angles).

So triangles  ABE and CDE are congruent by AAS.

5 0
3 years ago
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