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lana [24]
2 years ago
14

What is the answer to 4-(-6)+(-4)+3x0

Mathematics
2 answers:
Virty [35]2 years ago
8 0

Answer:

9

Step-by-step explanation:

Follow PEMDAS

4-(-6)+(-4)+3x\\4+6-4+3x\\6+3x\\6+3=9

insens350 [35]2 years ago
5 0

Answer:

6

Step-by-step explanation: 4-\left(-6\right)+\left(-4\right)+3\times0

<u><em /></u>

<u><em>Apply the Inverse Property of Addition</em></u>

<u><em /></u>-\left(-6\right)+3\times0

<u><em>Apply Zero Property of Multiplication</em></u>

<u><em /></u>-\left(-6\right)

<u><em>Determine the sign</em></u>

<u><em /></u>6=YOUR\ ANSWER

<em>I hope this helps you</em>

<em>:)</em>

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mia hired a moving company, it charged 500$ for service mia give them a 16% tip.How much did she tip the movers.
Novosadov [1.4K]

Answer:

$80

Step-by-step explanation:

First you take 500 and multiply by 16% or .16.

You should get 80.

A tip for the future is when you have a percentage just move the decimal place to the left twice.

ie. 50%=.50, 125%=1.25, 2%=.02

I hope this helps :)

6 0
2 years ago
Read 2 more answers
How much heat is released when 12. 0 grams of helium gas condense at 2. 17 K? The latent heat of vaporization of helium is 21 J/
aleksandr82 [10.1K]

The amount of heat released when 12.0g of helium gas condense at 2.17 K is; -250 J

The latent heat of vapourization of a substance is the amount of heat required to effect a change of state of the substance from liquid to gaseous state.

However, since we are required to determine heat released when the helium gas condenses.

The heat of condensation per gram is; -21 J/g.

Therefore, for 12grams, the heat of condensation released is; 12 × -21 = -252 J.

Approximately, -250J.

Read more on latent heat:

brainly.com/question/19863536

7 0
2 years ago
Electricity usage data consists of 45 months has a mean number of units consumed is 390.47 per month with a standard deviation o
neonofarm [45]

Answer:

The 95% confidence interval for the average monthly electricity consumed units is between 47.07 and 733.87

Step-by-step explanation:

We have the standard deviation for the sample. So we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 45 - 1 = 44

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 44 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0141

The margin of error is:

M = T*s = 2.0141*170.5 = 343.4

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 390.47 - 343.40 = 47.07 units per month

The upper end of the interval is the sample mean added to M. So it is 390.47 + 343.40 = 733.87 units per month

The 95% confidence interval for the average monthly electricity consumed units is between 47.07 and 733.87

6 0
2 years ago
Someone please help me find y.
WITCHER [35]
Here's y

y=<span>‌<span><span><span>−<span>8x</span></span>+29
       </span><span><span>−x</span>+<span>3

Hope this helps:)
</span></span></span></span>
7 0
3 years ago
What is the value of the expression x^2y–y+xy^2–x for x=4 and y=0.25?
stepan [7]

Answer:

0 (zero)

Step-by-step explanation:

{x}^{2} y - y + x {y}^{2}  - x  \\  =  {4}^{2} \times  0.25 - 0.25 + 4 \times  {0.25}^{2}  - 4 \\  = 16 \times  0.25 - 0.25 + 4 \times  0.0625- 4  \\  = 4 - 0.25 + 0.25 - 4 \\  = 0 \\  \\  \purple {\boxed{ \bold{ \therefore \:  {x}^{2} y - y + x {y}^{2}  - x  = 0}}}

8 0
3 years ago
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