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Alexeev081 [22]
3 years ago
13

HELP NEEDED ASAP FOR 10 POINTS

Mathematics
1 answer:
Luda [366]3 years ago
3 0

Answer:

Option D

Step-by-step explanation:

(10x + 13) + (12 + 9x) + ( 13x + 12) + 55 + 44 = 360

32x + 136 = 360

Subtract 136 from both sides;

32x = 224

Divide both sides by 32;

x = 7

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Let g be the function given by g(x)=x^2*e^(kx) , where k is a constant. For what value of k does g have a critical point at x=2/
ArbitrLikvidat [17]
G `( x ) =2x * e^{kx}  + k x^{2} *e^{kx} = \\  = xe^{kx}(2 + kx )
2 + k x = 0
k x = -2
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k = - 3
Answer: for k= - 3, the function g ( x ) have a critical point at x = 2/3. 
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Can you use a horizontal line test to determine if a relation is a function?Why or why not?
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Whats a reason why the emperors of rome didnt like jesus?
barxatty [35]

Answer: because they didn't believe that he really could perform miracles

Step-by-step explanation: I'm a christian

4 0
3 years ago
Five times the sum of a number and 27 is greater than or equal to six times the sum of that
AleksAgata [21]

The complete version of question:

<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>

Answer:

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

Step-by-step explanation:

As the description of the statement is:

'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>

<em />

As

  • <em>Five times the sum of a number and 27  </em>is written as: 5(x + 27)
  • <em>greater than or equal </em>is written as:  \geq
  • <em>six times the sum of that number and 26'  </em>is written as: 6(x + 26)

so lets combine the whole statement:

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

solving

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

<em />5x+135\ge \:6x+156<em />

<em />5x+135-135\ge \:6x+156-135<em />

<em />5x\ge \:6x+21<em />

<em />5x-6x\ge \:6x+21-6x<em />

<em />-x\ge \:21<em />

<em />\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}<em />

<em />\left(-x\right)\left(-1\right)\le \:21\left(-1\right)<em />

<em />x\le \:-21<em />

Therefore,

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

6 0
3 years ago
Find the length of the longest side
Ugo [173]

Answer:

32

Step-by-step explanation:

56/7=8 so that means that means 4x8=32

4 0
3 years ago
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