Plz send the Venn diagram of this...

Angle G in trapezoid FGHJ measures 135 degrees. Jasmine reflects the trapezoid over the x-axis. What is the measure of the image

butalik [34]

Answer:

Triangle EFG has vertices E(-3, 4), F(-5, -1), and G(1, 1)

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Not? Is t(n)=2⋅3n

Vera_Pavlovna [14]

Answer:

Step-by-step explanation: I am used to describing arithmetic sequences like this:

3

,

5

,

7

,

.

3,5,7,...3, comma, 5, comma, 7, comma, point, point, point

But there are other ways. In this lesson, we'll be learning two new ways to represent arithmetic sequences: recursive formulas and explicit formulas. Formulas give us instructions on how to find any term of a sequence.

To remain general, formulas use

n

nn to represent any term number and

a

(

n

)

a(n)a, left parenthesis, n, right parenthesis to represent the

n

th

n

th

n, start superscript, start text, t, h, end text, end superscript term of the sequence. For example, here are the first few terms of the arithmetic sequence 3, 5, 7, ...

4 0

3 years ago

Toby exercises 14 hours a week. John exercises 20% more than Toby and Jenny exercises two more hours than John. Which expression

Sedaia [141]

Answer: C. 18.8w

Step-by-step explanation:

Since Toby exercise 14hours a week, and John exercises 20% more than Toby

John increment in number of hours compared to Tobi will be;

20/100 ×14 = 2.8hrs

This shows John exercises 2.8hrs more than Tobi. Total number of hours exercised by John will become;

14+2.8 = 16.8hrs

Since Jenny exercises two more hours than John, Total number of hours exercised by Jenny will be;

16.8hrs+2hrs

= 18.8hrs/week

If Jenny exercise 18.8hrs in a week, it means she will exercise 18.8×w/1 in w weeks which gives 18.8w weeks.

5 0

3 years ago

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Find the area of the figure and round to the nearest hundredth

sweet [91]

Answer:

285.45

Step-by-step explanation:

If you multiply 17.3x16.5, you get 285.45, and when you round to the nearest hundredth, well, it gives you the same answer.

Therefore, the answer is 285.45.

5 0

3 years ago

Are your finances, buying habits, medical records, and phone calls really private? A real concern for many adults is that comput

Andrej [43]

Answer:

a)There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

b)There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

c)There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

Step-by-step explanation:

The binomial probability is the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes (commonly called a binomial experiment).

It is given by the following formula:

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of a success.

In this problem, a success is being concerned that employers are monitoring phone calls.

53% of adults are concerned that employers are monitoring phone calls, so $p = 0.53$

(a) Out of four adults, none is concerned that employers are monitoring phone calls.

Four adults, so $n = 4$ .

Is the probability of 0 successes, so x = 0.

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

$P = C_{4,0}.(0.53)^{0}.(0.47)^{4}$

$P = 0.0488$

There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

(b) Out of four adults, all are concerned that employers are monitoring phone calls.

Four adults, so $n = 4$ .

Is the probability of 4 successes, so x = 4.

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

$P = C_{4,0}.(0.53)^{4}.(0.47)^{0}$

$P = 0.0789$

There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

(c) Out of four adults, exactly two are concerned that employers are monitoring phone calls.

Four adults, so $n = 4$ .

Is the probability of 4 successes, so x = 2.

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

$P = C_{4,2}.(0.53)^{2}.(0.47)^{2}$

$P = 0.3723$

There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

3 0

3 years ago