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ioda
3 years ago
5

Evaluate each expression for a=7,b=4,and c=-3.

Mathematics
1 answer:
stiks02 [169]3 years ago
3 0

Answer:

Step-by-step explanation: 3a-5b= 3(7)-5(4)

                                                       =21-20

                                                       =<u>1</u>

7-3a+5a+15=7-3(7)+5(7)+15

                   =7-21+35+15

                   =-14+50

                   =<u>36</u>

15a^2-17(bc)^2=15(7)^2-17(4)(-3)^2

                         =105^2-204^2

                         =210-408

                         =<u>-198</u>

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Please Help What is the value of the expression? −34+(1/10÷2/5)
sweet-ann [11.9K]
Regarding your (1/10 divided by 2/5):  I'm going to regard this as

(1/10) divided by (2/5).  

First, write 

 1
---         
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The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
astraxan [27]

Answer:

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

Step-by-step explanation:

In two similar triangles:

The ratio of the areas of two triangle is equal to the square of their perimeters.

Let A and A' represents the area of two triangles and P and P' represents their perimeter.

Then they are related as:

\dfrac{A}{A'}=\dfrac{P^2}{P'^2}

We are given:

A=72 dm^2  , A'=50 dm^2

and P+P'=226 dm.-----------(1)

i.e. \dfrac{72}{50}=\dfrac{P^2}{P'^2}\\\\\dfrac{36}{25}=\dfrac{P^2}{P'^2}

on taking square root on both the side we get:

\dfrac{P}{P'}=\dfrac{6}{5}\\\\P=\dfrac{6}{5}P'

Now putting the value of P in equation (1) we obtain:

\dfrac{6}{5}P'+P'=226\\\\\dfrac{6P'+5\times P'}{5}=226\\\\\dfrac{6P'+5P'}{5}=226\\\\11P'=226\times 5\\\\11P'=1130\\\\P'=\dfrac{1130}{11}=102.7272

Hence,

P=226-102.7272=123.2727

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

6 0
3 years ago
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