the correct question is <span>The length of a rectangle is represented by 4a + 3b, and its width is represented by 3a-2b. Write a polynomial for the perimeter of the rectangle. What is the minimum perimeter of the rectangle if a=12 and b is a non-zero </span>whole number?
we know that Perimeter of a rectangle=2*[length + width] length=(4a+3b) width=3a-2b so P=2*[(4a+3b)+(3a-2b)]-----> P=2*[7a+b]-----> P=14a+2b
the answer part a) is A polynomial for the perimeter of the rectangle is P=14a+2b
Part b) for a=12 P=14*12+2b---------> P=168+2b <span>the minimum perimeter of the rectangle is for b=1 </span>so P=168+2*1-----> P=170 units
the answer part b) is the minimum perimeter of the rectangle is 170 units
Let AM be the distance between point A and the right wall and AN be the distance between A and the left wall. Δ AMB is an isosceles right triangle and Δ ANC is half of an equilateral triangle. Length of AM = 30 m. Length of AN = 1/2 · 80 = 40 m. The distance between the walls is: 30 m + 40 m = 70 m.
