the correct question is <span>The length of a rectangle is represented by 4a + 3b, and its width is represented by 3a-2b. Write a polynomial for the perimeter of the rectangle. What is the minimum perimeter of the rectangle if a=12 and b is a non-zero </span>whole number?
we know that Perimeter of a rectangle=2*[length + width] length=(4a+3b) width=3a-2b so P=2*[(4a+3b)+(3a-2b)]-----> P=2*[7a+b]-----> P=14a+2b
the answer part a) is A polynomial for the perimeter of the rectangle is P=14a+2b
Part b) for a=12 P=14*12+2b---------> P=168+2b <span>the minimum perimeter of the rectangle is for b=1 </span>so P=168+2*1-----> P=170 units
the answer part b) is the minimum perimeter of the rectangle is 170 units
28 degrees. This is because the first angle is 12 degrees, the third is x degrees and the second is 5x. You know that in a triangle the angles add up to 180 degrees so 12 + 5x + x = 180. Then you get 6x =168 and x =28 degrees. (**x being the thrid angle**)
