The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
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Answer:
DNE
Step-by-step explanation:
The the given table, we have;
As x approaches -14 from the left, at x = -14.001, p(x) = 1.96
As x approaches -14 from the right, at x = -13.999, p(x) = 1.97
The value of p(x) when x = -14 is 
= Undefined, or is not definable, therefore, p(x) Does Not Exist (DNE) when x = -14, and we have;
Does Not Exist, DNE.
Answer:
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