Question

SOLVE: High school precal

Answer 1

Tbh idk I just need help passing a class

Answer 2

Answer:

The anser is $ln(64y^2)$

Step-by-step explanation:

• There are two logarithm properties one should take into account to understand that $2ln8+2lny$ and $ln(64y^2)$ are equal expressions.
• The first property refeers to exponentials: $ln(x^n)=n\times{lnx}$.
• The second property is the follow: $ln(x.y)=ln(x)+ln(y)$ (distributive property of the logarithm of a product).
• Applying these two properties to the expression $ln(64y^2)$ results as follows:

1. $ln(68y^2)=ln(8y)^2$ because $8\times8=64$. Then, applying the first property means that $ln(8y)^2=2\times{ln(8y)}$
2. Finally, applying the second property of logarithms to the logarithm of a product implies: $2\times{ln(8y)}=2\times[ln(8)+ln(y)]= 2\times{ln(8)}+2\times{ln(y)}$, which is the expression we needed to arrive.