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kirill115 [55]
3 years ago
14

3) Mark bought a car for $22,500. The value of the car depreciates by 11% every year. How much can

Mathematics
1 answer:
Tatiana [17]3 years ago
7 0

Answer:

2475

What you do is $22,500 x 11%

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Find the HCF and LCM of 4x^2 - 36 ,2x^2 - 12x + 18 and 2x^2 + x - 21​
olga_2 [115]

Answer:

(x-3), 4 (x - 3)^2 (x + 3) (2 x + 7)

Step-by-step explanation:

Factor all the expressions,

1st expression= 4x^2 - 36=4(x^2-9)=4(x+3)(x-3)

2nd expression=2x^2 - 12x + 18 =2(x^2-6x+9)=2 (x - 3)^2=2(x-3)(x-3)

3rd expression=2x^2 + x - 21​=(x - 3) (2 x + 7)

HCF=Commo factor=(x-3)

LCF=Common factor*Remaining factor=4(x+3)(x-3)(x-3) (2 x + 7)=4 (x - 3)^2 (x + 3) (2 x + 7)

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3 years ago
A math club took a math test. Twelve of the members had an average score of 80. Eighteen of the members had an average score of
lisabon 2012 [21]
The class average was like i think 83 or 84
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Khan Academy btw
Irina-Kira [14]

Answer:

B and D

Step-by-step explanation:

\frac{2^{5} }{6^{5} } = (\frac{1}{3} )^{5}

\frac{2^{5} }{6^{5} } = 2^{5}*6^{-5}

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2 years ago
What type of model should be used to make a prediction from the given data?
GenaCL600 [577]
I think that the answer is quadratic
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3 years ago
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Help me I need help please anyone
jarptica [38.1K]

Answer:

1st,4th,5th option.

Step-by-step explanation:

Let evaluate each option.

A segment bisector is a line segment, ray, and/or line that bisects a line into two congruent parts. LM splits JK and KH into congruent parts. The first option is correct.

A perpendicular bisector is a line segment,ray and/or line that intersects a line segment,ray at a right angle. We don't have a perpendicular angle here and so that isn't a option.

M isn't a vertex of congruent angles as there is none in this figure.

The fourth and fifth option are correct. They both are on the segment bisector so they split the figure segments into two congruent parts. Since they are on the line segment and bisects it, they are considered the midpoint or middle point of the figure side.

7 0
3 years ago
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