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Assoli18 [71]
2 years ago
12

Chris received $50,000 from his grandparents as a graduation gift. So, he has decided to invest the money

Mathematics
1 answer:
GenaCL600 [577]2 years ago
7 0

Answer: $7142.86

Step-by-step explanation:

Let the amount to be invested in the bond be represented by y.

Based on this, the amount to be invested in the CD will be: = 50000 - y.

From the information given, yearly interest on bond is 12%, this will be:

= 12% × y = 0.12 × y = 0.12y

Also, interest on CD will be:

= 5% × (50000 - y)

= 0.05(50000 - y)

Then, the equation to get the amount to be invested in bond will be:

0.12y + 0.05(50000 - y) = 3000

0.12y + 2500 - 0.05y = 3000

0.12y - 0.05y = 3000 - 2500

0.07y = 500

y = 500/0.07

y = 7142.8571

y = 7142.86

The amount to be invested in bond will be $7142.86

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Answer:

2

Step-by-step explanation:

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2 years ago
The average amount of time that students use computers at a university computer center is 36 minutes with a standard deviation o
frosja888 [35]

Answer:

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 36, \sigma = 5

The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{40 - 36}{5}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881.

1 - 0.7881 = 0.2119

So 21.19% of the students use the computer for longer than 40 minutes.

Out of 10000

0.2119*10000 = 2119

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

8 0
3 years ago
At basketball practice you made 21 out of 80 shots. Which choice is closest to the percentage of shots you made?
love history [14]
Since this is a percentage, all you have to do is divide 21 from 80 and multiply that by 100
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The answer closest to this is 25%, so the answer is 25%

Hope this helped! :D


5 0
2 years ago
Read 2 more answers
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ANSWER: 7n-2

m-6n-3/m-13n-1

First you cross cancel m

then you get -6n-3/-13n-1

Thn you would subtract : 7n-2

3 0
3 years ago
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spayn [35]

Answer:

n = x * 3

Step-by-step explanation:

n is your "number"

5 0
2 years ago
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