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3 years ago

15

You find a piece of wood that is 10.23 cm long and your friend finds on ethat is 17.65 cm long how long would they be if you att

ached them?

1 answer:

sleet_krkn [62]3 years ago

5 0

Answer:
27.88

Explanation:
10.23 + 17.65 = 27.88

Hope this helps!!

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HELP! LOOK AT THE IMAGES BELOW

sineoko [7]

Answer:

(g+f)(x)=(2^x+x-3)^(1/2)

Step-by-step explanation:

Given

f(x)= 2^(x/2)

And

g(x)= √(x-3)

We have to find (g+f)(x)

In order to find (g+f)(x), both the functions are added and simplified.

So,

(g+f)(x)= √(x-3)+2^(x/2)

The power x/2 can be written as a product of x*(1/2)

(g+f)(x)= √(x-3)+(2)^(1/2*x)

We also know that square root dissolves into power ½

(g+f)(x)=(x-3)^(1/2)+(2)^(1/2*x)

We can see that power ½ is common in both functions so taking it out

(g+f)(x)=(x-3+2^x)^(1/2)

Arranging the terms

(g+f)(x)=(2^x+x-3)^(1/2) ..

5 0

3 years ago

Please help asap will give brainliest!!

Anit [1.1K]

Answer:

802

Step-by-step explanation:

802

6 0

3 years ago

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!

zalisa [80]

Answer:

The answe is 2/5m=4

Step-by-step explanation:

If he ate 4 of them, but it means he ate 2/5 muffins,

4 muffins = 2/5 muffins

You substitute x muffins for how much muffins she baked in all -

2/5 * x muffins = 4 or 2/5m = 4

Hope that helped :) <3

5 0

3 years ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection = </em>

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago

The formula for the area of a triangle is A = 1bh. Solve the formula for h. If the

love history [14]

Answer: H = 8 cm

Step-by-step explanation: Since a triangle's area is b times h/2, we know that two times 48 is 96, therefore we can opposite the equation so 12 is the base times the height (8 cm) is 96 divided by 2, there's your answer.

4 0

3 years ago

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