Answer:
a)
AB is on the latitude 30°N.
<u>Find AB:</u>
- AB = 2*3.142*6400*cos 30°*(32+35)/360 = 6482.15 km
BC is along longitude 35°W
<u>Find BC:</u>
- BC = 2*3.142*6400*(30 + 20)/360 = 5585.77 km
<u>Total distance traveled:</u>
- 6482.15 + 5585.77 = 12067.92 km
<u>Convert the distance to nautical miles:</u>
12067.92/1.86 = 6488.13 nautical miles
b)
<u>Find the average speed:</u>
- 6488.13/22 = 294.92 nautical miles / hour
<u>Note</u>. <em>This is unrealistically high speed for a ship, this must be a plane or the time given wrong.</em>
For the first problem, the answer is D, because every year, the graph goes down by about $4,500.
For problem two,
a. It's located in quadrant one because x and y are both positive (I've attached a graph with labeled quadrants for reference)
I'm unsure about b and c but I hope I helped with the others!
Answer:
The correct option is D.Any real number value of x satisfies the equation.
Hope it helps.............
Are you trying to graph it because it is in y=mx+b form.
Remember you can do anything to an equaiton as long as you do it to both sides
-x=4-3x
add 3x both sides
3x-x=4+3x-3x
2x=4+0
2x=4
divide 2
2x/2=4/2
2/2x=2
1x=2
x=2
