Answer:
quantity a is halfed
Corrected question;
A quantity a varies inversely as a quantity b, if, when b changes a changes in the inverse ratio. What happens to the quantity a if the quantity b doubles?
Step-by-step explanation:
Analysing the question;
A quantity a varies inversely as a quantity b,
a ∝ 1/b
a = k/b ......1
when b changes a changes in the inverse ratio;
Since the change at the same ratio but inversely, k = 1
So, equation 1 becomes;
a = 1/b
If the quantity b doubles,
ab = 1
a1b1 = a2b2
When b doubles, b2 = 2b1
a1b1 = a2(2b1)
Making a2 the subject of formula;
a2 = a1b1/(2b1)
a2 = a1/2
Therefore, when b doubles, a will be divided by 2, that means a is halfed.
Answer:
A. point B (-11,7) Point C (11,-7)
Step-by-step explanation:
Answer:
? = 5.12
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin B = opp/ hyp
sin 65= 5/ ?
? = 5/ sin 65
? =5.516889595
To the nearest hundredth
? = 5.12
Answer:
-3 5/12=k
Step-by-step explanation:
K+5/3= -7/4
subtract 5/3 from both sides
K= -7/4-5/3
lcm of 4 and 3 is 12
so
K= -21/12-20/12
K= -41/12
K= -3 5/12
