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3 years ago

Please help me!

Mathematics

2 answers:

RUDIKE [14]3 years ago

7 0

Answer:

B. 1/9

Step-by-step explanation:

The positive square root of "x^2 - 4x + 4" is "x - 2". That value is already given to you, 1/3. Just square 1/3 to get 1/9.

serious [3.7K]3 years ago

4 0

Answer:

B 1/9

Step-by-step explanation:

x − 2 = 1/3

Add 2 to both sides

X+2-2 = 1/3+2

x = 7/3

Put x = 7/2 into the expression x² − 4x + 4

(7/3)² - 4(7/3) + 4

49/9 - 28/3 + 4

= (49-84+36)/ 9

= 1/9

I hope this was helpful, please mark as brainliest

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Write each as the sum of two terms in the form t_n,r. t_5,3 , t_11,2 , t_15,13

Anarel [89]

The sum of two terms are:

t₅, ₃ = 8
t₁₁, ₂ = 13
t₁₅,₁₃ = 28.

<h3>What is the sum about?</h3>

The sum of two numbers is one that tells you to find the sum of two or more numbers, and as such, you have to add the numbers altogether.

t₅, ₃ = 5 + 3

= 8

t₁₁, ₂ = 11 + 2

= 13

t₁₅,₁₃ = 15 + 13

= 28.

Hence the correct sum of two terms are:

t₅, ₃ = 8
t₁₁, ₂ = 13
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2 years ago

At a pep rally 14 out of 20 students who entered the gym were carrying a backpack. Based on this information, if 1,400 students

kondaur [170]

Answer:

980 students

Step-by-step explanation:

14/20=x/1400

cross multiplication and then u get the equatiton 20x=19600

solve and get 980

4 0

3 years ago

Read 2 more answers

Complete the equation and tell which property you use 16+31=31_

Lorico [155]

Property to use for 16+31 is addition. 16+31=31+16. just reverse yhe numbers

6 0

3 years ago

Score: 0 of 1 pt

jonny [76]

Answer:

See attachment for graph

Step-by-step explanation:

Given

$y = x^2 - 3$

Required

The graph of the equation

First, we determine the range of y

$x = -3$

$y = x^2 - 3 \to y = (-3)^2 - 3 = 6$

$(-3,6)$

$x = -2$

$y = (-2)^2 - 3 = 1$

$(-2,1)$

$x = -1$

$y = (-1)^2 - 3 = -2$

$(-1,-2)$

$x=0$

$y = 0^2 - 3 = -3$

$(0,-3)$

$x = 1$

$y= 1^2 - 3 = -2$

$(1,-2)$

$x = 2$

$y =2^2 - 3 = 1$

$(2,1)$

$x = 3$

$y = 3^2 - 3 = 6$

$(3,6)$

<em>See attachment for graph</em>

7 0

3 years ago

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alexgriva [62]

Where is the equals sign in the second one? Are we supposed to solve for x?

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3 years ago