Question

) A rectangles length is 4 more than 3 times its width.

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Let the width of the rectangle be 'w'

According to the question length of the rectangle (l) is 4 more than 3 times it's width;

$\longrightarrow$ l = 3w + 4

Perimeter of rectangle = 152

Formula of perimeter of rectangle = 2(Length + Width)

So,

$\rm \implies 2(Length + Width) = 152 \\ \\ \rm \implies 2(3w + 4+ w) = 152 \\ \\ \rm \implies 2(4w + 4) = 152 \\ \\ \rm \implies 2 \times 4(w + 1) = 152 \\ \\ \rm \implies 8(w + 1) = 152 \\ \\ \rm \implies w + 1 = \dfrac{152}{8} \\ \\ \rm \implies w + 1 = 19 \\ \\ \rm \implies w = 19 - 1 \\ \\ \rm \implies w = 18$

$\therefore$ Width of the rectangle (w) = 18

Length of rectangle (l) = 3 × 18 + 4 = 58