To determine which line the point lies on, you can just plug in one of the numbers into the equations to see if it equals out.
(2, -1) I will use the 2 and plug it in for x in the equation.
y = 2x + 1
y = 2(2) + 1
y = 5 The point does not lie on this line because when x = 2, y = 5 (2, 5)
y = x + 5
y = 2 + 5
y = 7 The point does not lie on this line because when x = 2, y = 7 (2, 7)
y = 2x - 5
y = 2(2) - 5
y = 4 - 5
y = -1 The point does lie on this line because when x = 2, y = -1 (2, -1)
y = x - 2
y = 2 - 2
y = 0 The point does not lie on this line because when x = 2, y = 0 (2, 0)
-x - y = 1 . . . . . (1)
y = x + 3 . . . . . (2)
Putting (2) into (1), gives:
-x - x - 3 = 1
-2x = 1 + 3 = 4
x = 4/-2 = -2
From (2), y = -2 + 3 = 1
Therefore the two line will intersect at the point (-2, 1)
It is very important to read and understand the words of the problem before getting down to solving the given question. Numerous information's of immense importance are already given in the question. Those information's will come in handy while solving the question.
Let us assume the unknown number to be = x
Then
3x - 2 = 13
3x = 13 + 2
3x = 15
Dividing both sides of the equation by 3, we get
(3/3) * x = 15/3
1 * x = 5
x = 5
So the unknown number is 5. I hope the procedure is not very tough for you to understand.
Answer:
20.31 units to the nearest hundredth.
Step-by-step explanation:
We need to use the distance formula between the points and find their sum.
D1 = √((2-2^2 + (1+3)^2) = √16 = 4
D2 = √(-1-2)^2 + (3-1)^2) = √13
D3 = √(-3+1)^2 + (0-3)^2) = √13
D4 = √(-3+3)^2 + (-4)^2) = √16 = 4.
D5 = √(-3-2)^2 + (-4+3)^2) = √26.
Perimeter = D1+D2+D3+D4+D5
= 4+√13+√13 + 4 +√26
= 20.31 units.
