Step-by-step explanation:
-4+13=9
-16-(-29)=13F lower
1 feet = 0.3048 m
0.3048 m = 1 feet
1 m = (1/0.3048) feet
1600 m = 1600 * (1/0.3048) ≈ 5249.34
1600 m ≈ 5249.34 feet
Answer:
Work done will be equal to 5.2059 lb-ft
Step-by-step explanation:
We have given force F = 10 lb
Spring is stretched to 2 in
So x = 2 in
As 1 inch = 0.0833 feet
So 2 inch = 2×0.0833 = 0.1666 feet
From hook's law we know that F = Kx , here K is spring constant and x is spring elongation
So 
K = 60.024 lb/feet
Now new elongation x = 5 in
So 5 in = 5×0.0833 = 0.4165 feet
Work done is given by 
So 
So work done will be equal to 5.2059 lb-ft
We have the following functions:
f (x) = x-1
g (x) = 2x-3
For the sum we have:
f (x) + g (x) = (x-1) + (2x-3)
f (x) + g (x) = 3x - 4
For subtraction we have:
f (x) - g (x) = (x-1) - (2x-3)
f (x) - g (x) = -x + 2
For the product we have:
f (x) * g (x) = (x-1) * (2x-3)
f (x) * g (x) = 2x ^ 2 - 3x - 2x + 3
f (x) * g (x) = 2x ^ 2 - 5x + 3
For the quotient we have:
f (x) / g (x) = (x-1) / (2x-3)