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2 years ago

Solve for x. Round to the nearest tenth, if necessary.

Mathematics

1 answer:

DENIUS [597]2 years ago

6 0

Answer:

x=3.5 cm

Step-by-step explanation:

90/2 = 45 degrees

Soh Cah Toa

We have opposite and hypotenuse making sin.

Length×Sin(Angle)

5×Sin(45) = 3.53553cm

Rounded the the nearest tenth makes 3.5cm

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What is the initial value in the function 2x + 3y = 6?

maw [93]

<h2>Explanation:</h2><h2></h2>

The initial value of this function is the y-intercept. We know that the slope-intercept form of the equation of a line is given by:

$y=mx+b \\ \\ \\ Where: \\ \\ \\ m:slope \\ \\ b:y-intercept$

Writing our equation in slope intercept form:

$2x + 3y = 6 \\ \\ \\ \text{Subtract 2x from both sides}: \\ \\ 2x -2x+ 3y = 6-2x \\ \\ 3y=6-2x \\ \\ \\ \text{Divide both sides by 3}: \\ \\ y=\frac{6-2x}{3} \\ \\ y=-\frac{2x}{3}+2$

So the initial value is:

$b=3$

5 0

2 years ago

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ryzh [129]

Answer:

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Step-by-step explanation:

5 0

2 years ago

Subject : Maths<br> Level : High school<br> Topic : Surds<br> Points : 72

Mila [183]

Answer:

a = 5

Step-by-step explanation:

<u>Simplify:</u>

√5(√8 + √18) =
√5*8 + √5*18 =
√40 + √90 =
√4*10 + √9*10 =
2√10 + 3√10 =
(2 + 3)√10 =
5√10

<u>The value of a:</u>

a√10 = 5√10
a = 5

6 0

2 years ago

The sum of 7, -8 and 2 is less than zero. true or false

Usimov [2.4K]

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8 0

3 years ago

Phil's height is 51.2 cm, suzanne's height is 5'4", and suzanne's shadow lengthat gobblers knob is 76.2

8090 [49]

Answer:

$P_1 = 24cm$

Step-by-step explanation:

Represent:

Phil's height with P

Suzanne's height with S

Phil's shadow with P1

Suzanne's shadow with S1

So, we have:

$P = 51.2cm$

$S = 5'4"$

$S_1 = 76.2cm$

Required

Calculate the length of Phil's shadow --- Missing part of question

To do this, we make use of the following equivalent ratio.

$P:S = P_1 : S_1$

Convert $S = 5'4"$ to cm

$S = 5ft\ 4in$

$S = (5*30.48+ 4*2.54)cm$

$S = 162.56cm$

Substitute values for P, S and S1

$51.2cm : 162.56cm = P_1 : 76.2cm$

Express as fraction

$\frac{51.2cm}{162.56cm} = \frac{P_1 }{ 76.2cm}$

Make P1 the subject

$P_1 = 76.2cm * \frac{51.2cm}{162.56cm}$

$P_1 = 76.2cm * \frac{51.2}{162.56}$

$P_1 = \frac{76.2cm * 51.2}{162.56}$

$P_1 = \frac{3901.44cm}{162.56}$

$P_1 = 24cm$

<em>Hence, the length of Phil's shadow is 24 cm</em>

6 0

2 years ago