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Lerok [7]
2 years ago
8

Solve the equation 4(c-3)=8 What are two ways to start solving this equation? Choose BOTH ways Subtract 4 from both sides to get

c-3=4 Use the distributive property to get 4c-12=8 Divide both sides by 4 to get c-3=2 Use the distributive property to get 4c-3=8 Add 3 to both sides to get 4c=11
Mathematics
1 answer:
Pepsi [2]2 years ago
4 0

Answer:

b) Use the distributive property to get 4c-12=8

c) Divide both sides by 4 to get c-3=2

Step-by-step explanation:

Solve the equation 4(c-3)=8

What are two ways to start solving this equation?

We are given the Equation

4(c - 3) = 8

The two ways to start solving this Equation is given as:

1. 4(c - 3) = 8

We expand the brackets, using Distributive property

4c - 12 = 8

Or

2. 4(c - 3) = 8

Divide both sides by 4

4(c - 3)/4 = 8/4

c - 3 = 2

Therefore, options b and c is correct

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Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n
Svetradugi [14.3K]

Complete Question

Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150

Answer:

Normal sampling distribution can not be used

Step-by-step explanation:

From the question we are told that

    The  null hypothesis is  H_o  :  p =  0.015

     The  alternative hypothesis is    H_a  :  p  <  0.015

     

The  sample size is  n= 150

Generally in order to use  normal sampling distribution  

     The value  np  \ge  5

So  

         np =  0.015 * 150

         np =  2.25

Given that  np < 5   normal sampling distribution  can not be used

8 0
3 years ago
Multiples that are shared by two or more numbers are_______
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Answer:

it is called Common Multiples

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Answer:(9,-3)

Step-by-step explanation:

You just have to flip the numbers

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2 years ago
Decide whether each table could represent a proportional relationship. If the
Ymorist [56]

Answer:

Step-by-step explanation:

If given tables in the picture show the proportional relationship,

Number of wheels (w) ∝ Number of buses (b)

w ∝ b

w = kb

Here, k = proportionality constant

k = \frac{w}{b}

Number of buses (b)           Number wheels (w)             Wheels per bus (\frac{w}{b})

          5                                           30                               \frac{30}{5}=6              

          8                                           48                               \frac{48}{8}=6

         10                                           60                               \frac{60}{10}=6

         15                                           90                               \frac{90}{15}=6

Here, proportionality constant is 6.

Similarly, If number of wheels (w) ∝ Number of train cars (t)

w = kt

Here, k = proportionality constant

k = \frac{w}{t}

Number of train cars(t)          Number of wheels(w)     Wheels per train car (\frac{w}{t})

              20                                        184                           \frac{184}{20}=9.2

              30                                        264                           \frac{264}{30}=8.8

              40                                        344                           \frac{344}{40}=8.6

              50                                        424                           \frac{424}{50}=8.48

Since, ratio of w and t is not constant, relation between number of wheels and number of train cars is not proportional.

5 0
2 years ago
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