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Luden [163]
3 years ago
10

Simplify square root of 63

Mathematics
2 answers:
s2008m [1.1K]3 years ago
6 0
So 9 times 7 equals 63.  the square root of 9 is 3.  so you can take the 3 out and leave the 7 in the square root.  you end up with 3 times the square root of 7.
Vedmedyk [2.9K]3 years ago
4 0

Answer: \sqrt[3]{7}

Step-by-step explanation: To simplify the square root of 63, let’s first start by setting up a factor tree. A factor tree is very useful when finding the prime factorization of a number and can help us see it visually. Once we make our factor tree, we need to find out what two numbers multiplied together will give us a product of 63.

In this case, 9 multiplied by 7 will give us a product of 63 so we can write both 9 and 7 under 63.

Next, we can factor 9 because 7 cannot be factored other than itself and 1. The number 9 factors into 3 and 3 so we can write these numbers under 9. Now that we found the factors, we are done with our factor tree. Notice that we have two pairs of 3’s in our factor tree so a 3 can come outside of the radical.

Also, there is a 7 in our factor tree which does not pair up so it can stay inside of the radical. Therefore, the answer to this problem is \sqrt[3]{7}.

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For each ordered pair (x,y) determine whether it is a solution to the inequality 7x+2y&gt;_26
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The inequality is given as,

7x+2y>-26

Consider that any ordered pair (x,y) is said to be the solution of the inequality if the ordered pair gives a true result when substituted in the inequality.

Consider the ordered pair (4,-9),

\begin{gathered} 7(4)+2(-9)>-26 \\ 28-18>-26 \\ 10>-26 \end{gathered}

Clearly, the result is true. So it can be concluded that (4,-9) is a solution of the given inequality.

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Consider the ordered pair (3,4),

\begin{gathered} 7(3)+2(4)>-26 \\ 21+8>-26 \\ 29>-26 \end{gathered}

Clearly, the result is true. So it can be concluded that (3,4) is a solution of the given inequality.

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Consider the ordered pair (-4,0),

\begin{gathered} 7(-4)+2(0)>-26 \\ -28+0>-26 \\ -28>-26 \end{gathered}

Clearly, the result is false as -28 is not actually greater than -26.

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Consider the last ordered pair (-6,8),

\begin{gathered} 7(-6)+2(8)>-26 \\ -42+16>-26 \\ -26>-26 \end{gathered}

Note that the numbers on both sides of the inequality are identical. So there should be the symbol of equality, not inequality. So, it can be concluded that this ordered pair (-6,8) is not a solution of the given inequality.

Therefore, mark NO for the ordered pair (-6,8).

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