Which function displays this end behavior p
1 answer:
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Answer:
D
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
here (h, k) = (- 3, - 6), thus
y = a(x + 3)² - 6
To find a substitute (0, 0) into the equation
0 = 9a - 6 ⇒ a = =
y = (x + 3)² - 6 ← in vertex form
Expand (x + 3)² and distribute by
y = (x² + 6x + 9) - 6
= x² + 4x + 6 - 6
= x² + 4x ← in standard form