Answer:
x = log(33)/(3·log(2))
Step-by-step explanation:
The relevant logarithm relation is ...
log(a^b) = b·log(a)
__
Taking the logarithm of both sides of your equation gives ...
2^(3x) = 33
log(2^(3x)) = log(33)
(3x)·log(2) = log(33)
The coefficient of x is 3·log(2). Dividing by that gives the value of x:
x = log(33)/(3·log(2))
x ≈ 1.51851/(3·0.301030) ≈ 1.6814647
we know that
In an Arithmetic Sequence the difference between one term and the next is a constant

where
a1 is the first term
d is the common difference between terms
n is the number of months (in this problem)
case a) Mandy


------> equation 
in this equation the first month is April
case b) Bill


-------> equation 
In this equation the first month is May
With the equation
and the equation
calculate the attached table
therefore
the answer is
December
Answer:
180.25°
Step-by-step explanation:
AND DANG U SO CUTE!!!!
Answer:
its means a varieble or an unknown value
Step-by-step explanation: