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2 years ago

-4x-4y=24, 3x+10=y

1 answer:

3 0

$-4x-4y = 24~~...(i)\\\\3x +10 = y~~....(ii)\\\\\text{Substitute}~ y = 3x +10~ \text{in eq (i):}\\\\-4x -4(3x+10) = 24\\\\\implies -4x -12x -40=24\\\\\implies -16x =24+40\\\\\implies -16x = 64\\\\\implies x =- \dfrac{64}{16}\\\\\implies x = -4\\\\\text{Substitute}~ x = -4 ~ \text{in equation (ii) to find y:} \\\\y=3(-4) +10 = -12 +10 = -2\\\\\text{Hence,}~(x,y) = (-4,-2)$

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What is 6×9÷18+100-11+4

mojhsa [17]

6 × 9 ÷ 18 + 100 - 11 + 4

Use the order of operations to simplify:

Parentheses
Exponents
Multiplication
Division
Addition
Subtraction

6 × 9 ÷ 18 + 100 - 11 + 4

There are no parentheses or exponents, so multiplication comes first. Multiply 6 and 9.

54 ÷ 18 + 100 - 11 + 4

Next is division. Divide 54 by 18.

3 + 100 - 11 + 4

Finally, add and subtract from left to right.

103 - 11 + 4

92 + 4

<h3>Answer:</h3>

4 0

3 years ago

Please please help!!

sweet-ann [11.9K]

Answer:

Step-by-step explanation:

12/2=6

20/2=10

10-6=4

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3 years ago

MATH!<br><br><br> -4=2x+16<br><br> x=____?

Dima020 [189]

Answer: x=-10

Step-by-step explanation: hope this help

8 0

2 years ago

Please answer fast its timed

Alborosie

Answer:

f(5) = 22

f(9) = 34

Step-by-step explanation:

Plug in 5 and 9 separately for the equation of the x values. Multiply them each and add 7 to get these values 22 and 34.

4 0

3 years ago

A food company sells salmon to various customers. The mean weight of the salmon is 37 lb with a standard deviation of 2 lbs. The

brilliants [131]

Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

$\overline{X} = \frac{X_1+X_2+...+X_n}{n}$

If $X_1, ..., X_n$ are indentically distributed and independent, like in the situation of the problem, then the variance of $X_1 + .... + X_n$ will be the sum of the variances, in other words, it will be n times the variance of $X_1$ .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus $\overkine{X} = \frac{V(X_1)}{n}$ and as a result, the standard deviation of $\overline{X}$ is the standard deviation of $X_1$ divided by $\sqrt{n}$ .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

Restaurants: We have boxes with 9 salmon each, so it will be $\frac{2}{\sqrt{9}} = \frac{2}{3}$
Grocery stores: Each carton has 49 salmon, thus the standard deviation is $\frac{2}{\sqrt{49}} = \frac{2}{7}$
Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is $\frac{2}{\sqrt{64}} = \frac{1}{4}$

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

7 0

2 years ago