Ask question

Ask question

All categories

3 years ago

9

Brita has a monthly budget of x dollars. She spends $1,425 on her mortgage every month. One-third of her remaining budget is spe

nt on recreational activities. Which equation below can be used to determine the amount, in dollars, spent on recreational activities?

1 answer:

Morgarella [4.7K]3 years ago

7 0

Answer:

yikhjgmh

Step-by-step explanation:

86686

You might be interested in

Match the verbal expression (term) with its algebraic expression (definition).

UkoKoshka [18]

The matching of definitions and terms are done below.

Some number increased by two ⇒ b + 2
A variable decreased by two ⇒ x – 2
Product of an unknown value and two ⇒ 2z
Quotient of some number and two ⇒ a ÷ 2
An unknown value squared ⇒ y²

<h3>What is Algebra?</h3>

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

Match the verbal expression (term) with its algebraic expression (definition).

Some number increased by two ⇒ b + 2

A variable decreased by two ⇒ x – 2

Product of an unknown value and two ⇒ 2z

Quotient of some number and two ⇒ a ÷ 2

An unknown value squared ⇒ y²

More about the Algebra link is given below.

brainly.com/question/953809

#SPJ1

6 0

1 year ago

The table below shows four systems of equations:

Ede4ka [16]

To determine which system of equations would have the same solution, we evaluate each system of equations.

System 1 4x − 5y = 2, 3x − y = 8
x = 38/11
y = 26/11

<span>System 2 4x − 5y = 2, 3x − 2y = 1
x = 1/7
y = -2/7

System 3 4x − 5y = 2, 3x − 8y = 4
x = -4/17
y = -10/17

System 4 4x − 5y = 2, 10x − 9y = 4
x = 1/7
y = -2/7

</span><span>
Therefore, the correct answer is option 3. </span><span>System 2 and system 4 are equal, because the second equation in system 4 is obtained by adding the first equation in system 2 to two times the second equation in system 2.

4x− 5y = 2 2( 3x − 2y = 1)
----------------------- 10x - 9y = 4</span>

4 0

3 years ago

A jar contains 46 quarters and pennies. The total value of the coins is $4.30. Which system of equations can be used to find p,

Crazy boy [7]

Answer:

16 quarters

30 pennies

Step-by-step explanation:

q= quarters

p=pennies

set up a system of equations. One equation is for total value, the other is total # of coins.

q + p = 46

0.25q + 0.01p = 4.30 -> multiply this equation by 4 so you can subtract from the top equation

q + P =46

1q + 0.04p = 17.20

subtract the bottom equation from the top

0.96p = 28.8

divide by 0.96

p=30

substitute p in the top equation

q + 30 = 46

subtract 30 from both sides

q = 16

4 0

3 years ago

Now complete the square for 2x^2 + 16x + 3.

o-na [289]

Answer:

To complete the square the equation would be 2(x+4)^2-29

4 0

2 years ago

Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

$x^2-5x+7=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

$\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43$

2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0$

6. $k(x)=\frac{x+1}{x^2+x+29}$

$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

$\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102$

7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

$x=8,1$

The function is not defined for x=8 and x=1

Hence, function l is not defined for all real values.

8. $m(x)=\frac{x^2+5x-24}{x^2+11}$

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722$

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0

3 years ago