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2 years ago

1/3a = −5 What does a equal?

1 answer:

3 0

1/3 ⋅ = −5

1. Combine multiplied terms into a single fraction
1/3 = −5
1a/3 = -5

2. Multiply by 1
1a/3 = -5
a/3 = -5

3. Multiply all terms by the same value to eliminate fraction denominators
a/3 = -5
3 • a/3 = 3 (-5)

4. Cancel multiplied terms that are in the denominator
3 • a/3 = 3 (-5)
a = 3 (-5)

5. Multiply the numbers
a = 3(-5)
a = -5

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3/4x + 3y = 12 for when x = 5

Mila [183]

3/4(5)+3y=12
15/4+3y=12
3y=12-15/4
3y=33/4
y=33/4 /3
y=11/4

4 0

2 years ago

4x²-5x+3 + 2x²+7x-8<br><br><br> a. 6x²+2x-5<br> b. 6x²+12x-5<br> c. 6x²-2x+5<br> d. 6x²+2x11

mrs_skeptik [129]

Combine the like terms

(4x^2 + 2x^2) +(7x - 5x) + (3 - 8)
6x^2 2x -5

6x^2 + 2x - 5

Answer is A

3 0

2 years ago

Please help.<br> Is algebra.<br> PLEASE HELP NO LINKS OR FILES.<br> I don't want links.

Andru [333]

Answer:

Step-by-step explanation:

first, group the terms with the same power together and it would become (-9n⁵-4n⁵)+(n³-9n³)+(11n+6n). then, combine the terms in each group together which would get -13n⁵-8n³+17n as the answer

6 0

2 years ago

The polynomial -x^3-x^2+12x represents the volume of a rectangular aqautic tank in cubic feet. the length of the tank is (x+4).

Verizon [17]

Answer:

<h2>a. It should look for 3 linear factors.</h2><h2>b. There are 3 dimensions.</h2><h2>c. x = 1.7</h2><h2>d. Maximum value is 12.597</h2>

Step-by-step explanation:

$-x^{3} - x^{2} + 12 \timesx$ = $-x^{3} - 4 \timesx^{2} + 3 \timesx^{2} +12 \timesx$ = $-(x + 4) \timesx^{2} + 3 \timesx \times(x + 4)$ = $(x + 4) \timesx \times (x + 3)$

Hence the factorized form of the volume of the poly is $(x + 4) \timesx \times (x + 3)$

3 linear factors should needed to be look for.

The 3 dimensions are (x + 4), x, (x + 3).

Let, f(x) = $-x^{3} - x^{2} + 12 \timesx$

Now, $\frac{d f(x)}{dx}$ = $-3 \timesx^{2} -2 \timesx + 12$

Let $f1(x)$ = $-3 \timesx^{2} -2 \timesx + 12$ and $f2(x)$ = $\frac{d f1(x)}{dx}$ = $-3 \timesx -2$

The value will be maximum, if f1(x) = 0 and f2(x) < 0.

$f1(x) = 0$ \\ $3 \timesx^{2} + 2 \timesx -12 = 0$ \\ $x = \frac{- 2 + \sqrt{2^{2} + 4 \times3 \times12} }{2 \times3} , \frac{- 2 - \sqrt{2^{2} + 4 \times3 \times12} }{2 \times3}$

x = 1.69 ≅ 1.7 or x = -2.36 ≅ -2.4

Now f2(1.7) < 0.

At x = 1.7, the volume will be maximum.

The maximum value is f(1.7) = 12.597(approximately)

8 0

3 years ago

Solve for y:<br> 32x + 14y = 23

Alexxandr [17]

Y= -16/7x + 23/14

I hope this helps it has been a while since I have done these

3 0

3 years ago