All categories

3 years ago

What's the slope? Help plssss

Mathematics

2 answers:

frosja888 [35]3 years ago

5 0

Answer:

m = $-\frac{4}{3}$

Step-by-step explanation:

The slope is $-\frac{4}{3}$ because the line goes <em>down</em> from <em>left to right</em> and it goes down 4 units and right 3 units.

STALIN [3.7K]3 years ago

4 0

Answer:

- $\frac{4}{3}$

Step-by-step explanation:

Slope is $\frac{y2-y1}{x2-x1}$ so insert 2 points there and you get -4/3

Please give brainliest.

You might be interested in

This one a little weird

Ludmilka [50]

Answer:

It might be 10 but tell me if I'm right or wrong

Step-by-step explanation:

6 0

3 years ago

How to convert improper fraction to a mixed or whole number (reduce to lowest terms): 24/9

MakcuM [25]

How to convert improper fraction to a mixed or whole number (reduce to lowest terms): 24/9

6 0

3 years ago

Write 0.24 as a fraction in simplest form

guapka [62]

The answer is 24/100

4 0

3 years ago

Suppose the contestants were asked to make two batches of their recipes instead of one batch. Would the value for the amount of

kirill [66]

Answer:

yes

Step-by-step explanation:

If all contributors to the distribution are doubled, the value of any particular item in the distribution will be double what it was. That is, it will be different.

4 0

3 years ago

Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).

lions [1.4K]

Check the picture below. so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}$

$(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill$

$\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}$

6 0

2 years ago