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2 years ago

Use the relationship between the angles in the figure to answer the question.

Mathematics

2 answers:

Serggg [28]2 years ago

8 0

Answer:

x=52°

Step-by-step explanation:

because of the vertical angles theorem

Nookie1986 [14]2 years ago

3 0

Answer:

x=52°

Step-by-step explanation:

the vertical angles theorem

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Suppose that 2 people exercising in an enclosed room are each generating about 2.400 BTUs of body heat per

noname [10]

Answer:

0.002 BTUs per cubic foot heat is produced per hour

Step-by-step explanation:

Given:

Number of person = 2

Amount of heat produced by one person = 2.400 BTU

Dimension of the room = 20 ft x 12 ft x 10 ft

To Find:

How many BTUs per cubic foot do they produce in 1 hour = ?

Solution:

E = $\frac{ \text{(2400 Btu/ person hr}) (\text{Number of Hours}) (\text{Number of persons }) }{\text {volume of the room}}$

Substituting the values

E = $\frac{ \text{(2400 Btu/ person hr}) (1) ( 2) }{20 ft \times 12 ft \times 10 ft}$

E = $\frac{4.800}{2400}$

E = 0.002 BTU per cubic feet

7 0

2 years ago

Read 2 more answers

Use the cubic model y = 5a3 - 2a2 + a - 45 to find the value of y when x = 4.

Naddik [55]

Assuming 5a3 equals 5a^3, and the same for everything else, you would plug in 4 for a, so 5(4)^3 - 2(4)^2 + 4 - 45, which equals 247.

3 0

3 years ago

Tell whether this statement is sometimes, always, or never true. Identify the answer with a sketch. If B is a point between A an

Ksivusya [100]

The statement is always true

7 0

3 years ago

30+ Points!!!<br> 5. Solve the following inequalities.<br> a) 2 log3x – 2 logx3 -3 <0

Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

$\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}$

$2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)$

$\mathrm{Simplify}$

$-2logx^3-3$

$\mathrm{Add\:}3\mathrm{\:to\:both\:sides}$

$-2logx^3-3+3$

$\mathrm{Simplify}$

$-2logx^3$

$Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)$

$\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)$

$\mathrm{Simplify}$

$2lx^3og>2\log ^3\left(x\right)-3$

$\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0$

$\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\$

$\mathrm{Simplify}$

$g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0$

Step-by-step explanation:

6 0

3 years ago

Out of the 40 students in the 7th grade 60% of the students carry cell phones. What fraction of the students carry a cell phone?

nexus9112 [7]

If you have 60% out of 40 students that is 24 students

6 0

3 years ago

Read 2 more answers