To calculate the relative vector of B we have to:
![P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]](https://tex.z-dn.net/?f=P_B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C3%5C%5C-2%5C%5C3%2F2%5Cend%7Barray%7D%5Cright%5D)
The coordenates of:
, with respect to B satisfy:
Equating coefficients of like powers of t produces the system of equation:
After solving this system, we have to:
And the result is:
Learn more: brainly.com/question/16850761
Okay so you know a straight line is equal to 180 degrees, so you set them up in an algebraic equation. (5x+2)+48=180 subtract 48 first to get 5x+2=132 Subtract the 2 this time to get 130. Now you end up with 5x=130. Here you divide 130 by 5 to get X=26. If you just need to find the degree of that angle tho you can stop after the first subtraction because the math tells you (5x+2)=132 degrees.
X is positive 2 and y is positive 1
So it's 2.5 inches, so it would be 15 miles, because 6+6+3=15.
“d”
you know b cannot work because the x is raised to the x^2 which would be a diff graph
a does not work because -x^3 the graph would be flipped
c is incorrect because the five is in the negative region; not positive
