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Neporo4naja [7]
3 years ago
14

Marty collects colorful paper clips. Each week he is sure to add exactly five new paper clips to his collection. Make a table re

presenting this situation. Is the number of paper clips and arithmetic or geometric sequence? How do you know? I need the answer by today please​. Whoever answer is correct I will make brainliest​
Mathematics
1 answer:
ruslelena [56]3 years ago
7 0

Answer:

all of them

Step-by-step explanation:

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There are 9 socks in a bag. 1 of those socks is blue.
inessss [21]
1/9 or 11/100

Hope that helps
4 0
3 years ago
I have been stuck on this question please help
Hatshy [7]

Answer:

  • 3⁷

Step-by-step explanation:

  • (3⁴)⁻² * (3⁵)³ =
  • 3⁴⁽⁻²⁾*3⁵⁽³⁾ =
  • 3⁻⁸*3¹⁵ =
  • 3⁻⁸⁺¹⁵ =
  • 3⁷

Correct option is B. 3⁷

3 0
2 years ago
Write 37 99 as a decimal. A) 0.037 B) 0.37 C) 0.37 D) 3.73 (ALSO there are 2 of the .37 in the problem so im not sure what i hav
Anastaziya [24]

Answer:

Step 1: Address input parameters & values.

Input parameters & values:

The fraction number = 37/99

Step 2: Write it as a decimal

37/99 = 0.3737

0.3737 is the decimal representation for 37/99

Answer is 0.3737 repeating.

Hope this helps! Plz mark brainliest! ☜(゚ヮ゚☜)

4 0
3 years ago
Solve each triangle. Round your answers to the nearest tenth.<br>show work If possible ​
kvasek [131]
<h2>Answer:</h2>

∠ABC = 76°

BC = 20.1

CA = 28.0

<h2>Step-by-step explanation:</h2>

Solving the triangle means finding all unknown angles and sides of the triangle.

(i) Two of the angles (∠BCA = 60° and ∠CAB  = 44°) are given. To find the third angle (∠ABC), use one of the theorems stating <em>that the sum of angles of a triangle is equal to 180°.</em>

Therefore, the sum of angles of the triangle ABC is 180°. i.e

∠ABC + ∠BCA + ∠CAB = 180°

=> ∠ABC + 60° + 44° = 180°

=> ∠ABC + 104° = 180°

=> ∠ABC = 180° - 104°

=> ∠ABC = 76°

(ii) One side (BA) of the triangle is given. To get the other sides, we use the sine rule as follows;

=> \frac{sin60}{25} = \frac{sin44}{BC} = \frac{sin76}{CA}

=> \frac{sinBCA}{BA} = \frac{sinCAB}{BC} = \frac{sinABC}{CA}

<em>Substitute the necessary values</em>

\frac{sin60}{25} = \frac{sin44}{BC} = \frac{sin76}{CA}      ---------------------(ii)

(a) To get side BC, use the first two terms of equation (ii)

\frac{sin60}{25} = \frac{sin44}{BC}

<em>Cross multiply</em>

BC x sin 60 = 25 x sin 44

BC x 0.8660 = 25 x 0.6947

0.8660 x BC = 17.3675

BC = \frac{17.3675}{0.8660}

BC = 20.05

=> BC = 20.1 to the nearest tenth

(b) To get CA, use any two terms of equation (ii). Using the first and third terms, we have;

\frac{sin60}{25} = \frac{sin76}{CA}

<em>Cross multiply</em>

CA x sin 60 = 25 x sin 76

CA x 0.8660 = 25 x 0.9703

0.8660 x CA = 24.2575

CA = \frac{24.2575}{0.8660}

CA = 28.01

=> CA = 28.0 to the nearest tenth

5 0
3 years ago
Can someone pls help with this
Eddi Din [679]
:
You put 57 in F (on the left side)
You put 49 in S ( on the right side)

Have a great day
5 0
3 years ago
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