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koban [17]
4 years ago
10

Here is the question | | | | v

Mathematics
1 answer:
raketka [301]4 years ago
3 0

Answer:

16.5 square feet

Step-by-step explanation:

The logo consists of

  • rectangle with sides of 3 ft and 1.5 ft;
  • trapezoid with bases 3 ft, 4 ft and height of 3 ft;
  • triangle with base of 1.5 ft and height of 2 ft.

<u>The area of rectangle:</u>

A_{rectangle}=1.5\ ft\times 3\ ft=4.5\ ft^2

<u>The area of trapezoid:</u>

A_{trapezoid}=\dfrac{3\ ft+4\ ft}{2}\times 3 \ ft=3.5\ ft\times 3 \ ft=10.5 \ ft^2

<u>The area of triangle:</u>

A_{triangle}=\dfrac{1}{2}\times 1.5\ ft\times 2 \ ft=1.5\ ft^2

Hence, <u>the area of logo:</u>

A=A_{rectangle}+A_{trapezoid}+A_{triangle}=4.5\ ft^2+10.5\ ft^2+1.5\ ft^2=16.5\ ft^2

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Answer:

5)  DE = 7 units and DF = 4 units

6)  ST = 8 units

\textsf{7)} \quad \sf OM=\dfrac{3}{2}\:units

8)  x ≤ -3 and x ≥ 3

Step-by-step explanation:

<u>Information from Parts 1-4:</u>

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  • f(x)=-x+3
  • g(x)=x^2-9
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<h3><u>Part (5)</u></h3>

Points A and D are the <u>points of intersection</u> of the two functions.  

To find the x-values of the points of intersection, equate the two functions and solve for x:

\implies g(x)=f(x)

\implies x^2-9=-x+3

\implies x^2+x-12=0

\implies x^2+4x-3x-12=0

\implies x(x+4)-3(x+4)=0

\implies (x-3)(x+4)=0

Apply the zero-product property:

\implies (x-3)= \implies x=3

\implies (x+4)=0 \implies x=-4

From inspection of the graph, we can see that the x-value of point D is <u>negative</u>, therefore the x-value of point D is x = -4.

To find the y-value of point D, substitute the found value of x into one of the functions:

\implies f(-4)=-(-4)=7

Therefore, D = (-4, 7).

The length of DE is the difference between the y-value of D and the x-axis:

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The length of DF is the difference between the x-value of D and the x-axis:

⇒ DF = 4 units

<h3><u>Part (6)</u></h3>

To find point S, substitute the x-value of point T into function g(x):

\implies g(4)=(4)^2-9=7

Therefore, S = (4, 7).

The length ST is the difference between the y-values of points S and T:

\implies ST=y_S-y_T=7-(-1)=8

Therefore, ST = 8 units.

<h3><u>Part (7)</u></h3>

The given length of QR (⁴⁵/₄) is the difference between the functions at the same value of x.  To find the x-value of points Q and R (and therefore the x-value of point M), subtract g(x) from f(x) and equate to QR, then solve for x:

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Length OM is the difference between the x-values of points M and the origin O:

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Therefore, OM = ³/₂ units.

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