Gabrielle's age is three times Mikhail's age. The sum of their ages is 20. What is Mikhail's age?

2 answers:

5 0

You can convert this problem into an equation.
3x + x = 20
When simplified, the problem is 4x = 20
You can easily solve for x, which is 5.
Mikhail’s age is 5 years old.
Can I have brainliest?

PtichkaEL [24]2 years ago

4 0

Answer:

Mikhail is 5 years old

Step-by-step explanation:

Represent each member with a variable.

X= Gabrille

Y=Mikhail

X+Y=20 (sum of their ages is 20)

X=3y (Gabrille is 3 times Mikhails age)

Substitute 3Y into the first equation (simultaneous equation)

. 3y+y=20

. 4y=20 (divide both sides by 4)

y=5

To check your answer.

X+5=20

X=20-5

X=15

15 is 5 times 3.

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Alton shoveled snow on 4/6 of his driveway before lunch then he shoveled 2/6 of it after lunch how much more of his driveway did

xxMikexx [17]

Answer:

Alton shoveled 1/3 more before lunch than after lunch.

Step-by-step explanation:

Subtracting 2 values-

4/6 and 2/6

Subtract-

Since the denominators you are able to subtract.

4/6 - 2/6 = 2/6

Simplify-

2/6 = 1/3

Alton shoveled 1/3 more before lunch than after lunch.

3 0

4 years ago

In the figure, if m∠ABD = 120º, then m∠ADC =? º.

Anna11 [10]

The figure that this question is referring to is attached. We must use the Law of Sines to solve this question, which is as follows:

a/sinA = b/sinB = c/sinC

This applies to any triangle. We are told that ∠ABD = 120º. We are asked to solve for ∠ADC. We know that ∠ADC + ∠ADB = 180º. If we assign ∠ADC = x, then ∠ADB = 180º - x. We can now apply the law of sines to this data.

35/sin120 = 30/sin(180-x)
sin(180-x) = (30/35)(sin120)
sin(180-x) = 0.742
sin-1(sin(180-x)) = sin-1(0.742)
180 - x = 48º
x = 132º

We have already assigned x = ∠ADC; therefore, ∠ADC = 132º.