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murzikaleks [220]
3 years ago
8

How many possible outcomes are there?​

Mathematics
1 answer:
Natali [406]3 years ago
3 0
I can only see half the image
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Harry Julie’s best friend also paid $25.00 for three T-shirt’s at the sale at JCPenny the sale price saved harry 30% of the orig
Rasek [7]

30%25=7.5

25-7.5=17.5

So the original price of Harry's three T-shirts will be $17.50

5 0
4 years ago
65006500 is 666 thousands plus 555 hundreds.
madam [21]

Answer:

Choice C

Step-by-step explanation:

5 Thousand  + 15 hundred = 6500

8 0
3 years ago
Evaluate the summation of 3 times negative 2 to the n minus 1 power, from n equals 1 to 5. A) −93. B) −33. C) 33. D) 93
lions [1.4K]
∑ ( from n = 1 to n =5 ) 3 · ( -2 ) ^( n -1 )
a 1 = 3 · ( -2 ) ^0 = 3
a 2 = 3 · ( - 2 ) = - 6
a 3 = 3 · 4 = 12
a 4 = 3 · ( - 8 ) = - 24
a 5 = 3 · 16 = 48
3 - 6 + 12 - 24 + 48 = 33
Answer: C ) 33
4 0
3 years ago
Read 2 more answers
APQR and ARST are shown.<br> S<br> R.<br> P<br> 440<br> T<br> What is mZQPR?<br> m/OPR
Serga [27]

Answer:

∠ QPR = 56°

Step-by-step explanation:

Δ RST is isosceles ( 2 congruent sides ) , then base angles are congruent

∠ SRT = \frac{180-44}{2} = \frac{136}{2} = 68°

∠ PRQ and ∠ SRT are vertically opposite angles and are congruent , so

∠ PRQ = 68°

Δ PRQ is isosceles ( 2 congruent sides ), then base angles are congruent , so

∠ QPR = \frac{180-68}{2} = \frac{112}{2} = 56°

3 0
3 years ago
Read 2 more answers
A manager is comparing wait times for customers in a coffee shop based on which employee is
anyanavicka [17]

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

H_0: \mu_A - \mu_B = 0

At the alternative hypothesis, it is tested if there is difference, that is:

H_1: \mu_A - \mu_B = 0

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2

\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4

For the distribution of differences, we have that:

\overline{x} = \mu_A - \mu_B = 73 - 74 = -1

s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447

<h3>What is the test statistic?</h3>

It is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{-1 - 0}{0.447}

t = -2.24

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

8 0
2 years ago
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