1. x = z/y 10. a = 2s - b - c
2. d = St 11. m = p/n
3. n = N/r 12. f = 2jg
4. T = C/R 13. b = -a + 2c
5. m = Ln 14. q = 4p/r
6. u = v - at 15. C = -L + 2a + 3b
7. p = r/q 16. a = 4d - 2b - 3c
8. y = X - 2z 17. c = b^2 - a^2
9. b = 3c - 2a
18. r = -p^2 + q^2 + 3
19. r = t - 2s
phew, that was a lot. i hope this helps you and that you get a good grade!!
Answer:
This is an impossible question. This is because it is less than -80 but when you add the 5 it is -70 therefore it must be -75. But it saying it is below -80 therefore this is an impossible question
I believe the answer you are looking for is 42.
108 x 7 = 756
756 / 18 = 42
Answer:
73.1 cm
Step-by-step explanation:
In the drawing, the rubber track is in black and the wheels are in light gray.
As we can see in the figure, the rubber track will have a length of two halfs of a circunference of radius 8 cm plus six diameters of 8 cm. So the total length is:
Length of rubber track = pi * 8 + 6 * 8 = 25.13 + 48 = 73.133 cm
Rounding to one decimal place, we have that the length is 73.1 cm
In 6 ounces of coffee, there are 50 mg of caffeine
In 1 ounce of coffee there are 50/6 mg of caffeine or 8.33 mg caffeine
8.33 is equivalent to 83.3%
