Y=3x+2 when x=-3
=> y= 3(-3)+2 = -9+2 =-7
Answer:
S(C(x)) = –0.14x2 + 140; $108.50
Step-by-step explanation:
did the assignment
(a) Compare your quadratic for h to the general quadratic ax² +bx +c. Perhaps you can see that ...
a = -16
b = 128
You use these numbers in the given formula to find the time when the ball is highest.
t = -b/(2a) = -128/(2(-16)) = 4 . . . . . . the time at which the ball is highest
(b) Evaluate the quadratic to find the height at t=4.
h = -16(4)² +128(4) +21
h = -256 +512 +21
h = 277
The maximum height of the ball is 277 ft.
i need help in that answer too. i was just bout to ask this one
Answer:To prove the relationship about the length of a midsegment, I can use the properties of parallel lines and transversals. If I draw at least two midsegments, I see that they form congruent triangles within the original triangle, ∆ABC. I can prove the congruence of these triangles using triangle congruence criterion, and then use properties of congruent triangles and the Transitive Property to show that the length of the midsegment is half the length of the side it is parallel to.
Step-by-step explanation: