Item 10 Find the median, first quartile, third quartile, and interquartile range of the data. 38,55,61,56,46,67,59,75,65,58
jok3333 [9.3K]
I think the median is 58.5, the first quartile is 50.5, the third quartile is 66, and finally, the interquartile range is <span>12.75.</span>
Answer:1) 32. 2). 3) 21. 4) 4
Step-by-step explanation: 1) 4*8=32m, 2) I don't know, 3) 6*7=42 for the area of a square but since a triangle half it so its 21, An the last is by 4 for example 4*10=40 but if doubled its 20*8 and that equals 160. and 160/40=4
Answer:
d=-5
Step-by-step explanation:
-4d-37=7d +18
move the terms to its correct side
-4d-7d=18+37
calculate the like terms together.
-11d=55
divide both sides by -11. both of the negavtive (-11) will cancel out and become d on the left and on the right 55 will be divided by -11 = -5. the 5 is negative because there's a negative -11 if there were a postive 11 it will be 5 instead of D=-5
Answer:
The y intercept is 3
(0,3)
Step-by-step explanation:
4x+2y=6
To find the y intercept, set x =0 and solve for y
4(0) +2y = 6
0+2y = 6
Divide by 2
2y/2 = 6/2
y =3
The y intercept is 3
(0,3)
Answer:
Sum of the opposite pair of a cyclic quadrilateral is 180°.
c= 180-102= 78°
c= 180-102= 78°d= 180-92= 88°
<em><u>intercepted arc</u></em>
=>2(102°)= 140+a°
a=64°
<u>Simillarly</u>
=> 2(d°)= a°+b°
b°= 112°
so ....
<u>a=64°</u>
<u>a=64°b=112°</u>
<u>a=64°b=112°c=78°</u>
<u>a=64°b=112°c=78°d=88</u>
<em><u>hope it helps you</u></em><u> </u><u>.</u><u>.</u><u>.</u><u>.</u>
