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Vedmedyk [2.9K]

3 years ago

5

Hurry pls it’s very confusing

2 answers:

aev [14]3 years ago

6 0

Answer:

1/4

Step-by-step explanation:

choose two ordered pairs from the data and do y2 - y1 / x2 - x1

hope i helped <3

Jobisdone [24]3 years ago

5 0

Answer:

1/4

Step-by-step explanation:

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What is the sum of three tenths plus thirty nine hundredths equals blank a thirty six hundredths b forty two hundredths c sixty

ad-work [718]

Answer:c- sixty nine hundredths

Step-by-step explanation:

three tenths can be expressed in decimal as 3/10

thirty nine hundredths can be expressed in decimal as 39/100

Therefore the sum of three tenths plus thirty nine hundredths equals

3/10 +39/100

We first find the l.c.m of the two fractions equals 100 so we have 100 as the denominator

then 100 divided by 10 multiplied by 3 +100 divided by 100 multiplied by 39 as illustrated below gives the answer

3/10 +39/100

=30+39/100

=69/100= sixty nine hundredths

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3 years ago

Jethro walked at an average speed of 3 miles per hour for 2 hours. Randy walked at an average of 4 miles per hour for 3 hours. W

Vedmedyk [2.9K]

C.
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3 years ago

Which expression is equivalent to 9^-2?<br> –81<br> –18<br> 1/81<br> 1/18

Kaylis [27]

(9)^-2 = (1/9)^2 = 1/81

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3 years ago

Read 2 more answers

If c is the number of cats, which variable expression represents the phrase

Inessa05 [86]

the answer would be A.) C+15

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3 years ago

I am having trouble with this relative minimum of this equation.<br>

Norma-Jean [14]

Answer:

So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach. You have to let me know if you want this done another way.

Here are some rules I'm going to use:

$(f+g)'=f'+g'$ (Sum rule)

$(cf)'=c(f)'$ (Constant multiple rule)

$(x^n)'=nx^{n-1}$ (Power rule)

$(c)'=0$ (Constant rule)

$(x)'=1$ (Slope of y=x is 1)

$y=4x^3+13x^2-12x-56$

$y'=(4x^3+13x^2-12x-56)'$

$y'=(4x^3)'+(13x^2)'-(12x)'-(56)'$

$y'=4(x^3)'+13(x^2)'-12(x)'-0$

$y'=4(3x^2)+13(2x^1)-12(1)$

$y'=12x^2+26x-12$

Now we set y' equal to 0 and solve for the critical numbers.

$12x^2+26x-12=0$

Divide both sides by 2:

$6x^2+13x-6=0$

Compaer $6x^2+13x-6=0$ to $ax^2+bx+c=0$ to determine the values for $a=6,b=13,c=-6$ .

$a=6$

$b=13$

$c=-6$

We are going to use the quadratic formula to solve for our critical numbers, x.

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-13 \pm \sqrt{13^2-4(6)(-6)}}{2(6)}$

$x=\frac{-13 \pm \sqrt{169+144}}{12}$

$x=\frac{-13 \pm \sqrt{313}}{12}$

Let's separate the choices:

$x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}$

Let's approximate both of these:

$x=0.3909838 \text{ or } -2.5576505$ .

This is a cubic function with leading coefficient 4 and 4 is positive so we know the left and right behavior of the function. The left hand side goes to negative infinity while the right hand side goes to positive infinity. So the maximum is going to occur at the earlier x while the minimum will occur at the later x.

The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

We could also verify this with more calculus of course.

Let's find the second derivative.

$f(x)=4x^3+13x^2-12x-56$

$f'(x)=12x^2+26x-12$

$f''(x)=24x+26$

So if f''(a) is positive then we have a minimum at x=a.

If f''(a) is negative then we have a maximum at x=a.

Rounding to nearest tenths here: x=-2.6 and x=.4

Let's see what f'' gives us at both of these x's.

$24(-2.6)+25$

$-37.5$

So we have a maximum at x=-2.6.

$24(.4)+25$

$9.6+25$

$34.6$

So we have a minimum at x=.4.

Now let's find the corresponding y-value for our relative minimum point since that would complete your question.

We are going to use the equation that relates x and y.

I'm going to use 0.3909838 instead of .4 just so we can be closer to the correct y value.

$y=4(0.3909838)^3+13(0.3909838)^2-12(0.3909838)-56$

I'm shoving this into a calculator:

$y=-58.4654411$

So the approximate relative minimum is (0.4,-58.5).

If you graph $y=4x^3+13x^2-12x-56$ you should see the graph taking a dip at this point.

3 0

3 years ago