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dezoksy [38]
2 years ago
11

Which shows the correct way to use the rule "multiply by the reciprocall for the expression below? 5 divided by 2/9

Mathematics
1 answer:
tatuchka [14]2 years ago
6 0
5x9/2 because multiplying by reciprocals are basically flipping the fraction and multiplying.
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If Sarah is planning a trip to an amusement park, and 410 people are going, how many buses are needed to transport everyone if 4
ladessa [460]

Answer: <u>11.</u>

Step-by-step explanation: All you'd have to do in order to achieve this answer is by dividing 410 by 40 which gives you the answer of 10.25. In order to fit everyone they'll need a rounded number of buses; equalling 11.

3 0
2 years ago
Read 2 more answers
The table shows the speeds of several runners on a track team. What is the speed, in feet per minute, of the fastest runner?
Ipatiy [6.2K]
Where is the table? I would love to help!
3 0
3 years ago
1. Rewrite the expression. Use an exponent, rather than repeated multiplication. (–4)(–4)
AlekseyPX
-4^2 is the same as -4*-4

-4*-4=16

-4^2= 16 

-4^2 is the exponent.

I hope this helps!
~kaikers
4 0
3 years ago
Find a cubic function f(x) = ax3 + bx2 + cx + d that has a local maximum value of 4 at x = −3 and a local minimum value of 0 at
Vinvika [58]
The formula is f(x) = a x ^ 3 + b x ^ 2 + c x  + d 
f '(x) = 3ax^2 + 2bx + c. 
f(- 3) = 3 ==> - 27a + 9b - 3c + d = 3 
f '(- 3) = 0 (being a most extreme) ==> 27a - 6b + c = 0. 
f(1) = 0 ==> a + b + c + d = 0 
f '(1) = 0 (being a base) ==> 3a + 2b + c = 0. 
- 
Along these lines, we have the four conditions 
- 27a + 9b - 3c + d = 3 
a + b + c + d = 0 
27a - 6b + c = 0 
3a + 2b + c = 0 
Subtracting the last two conditions yields 24a - 8b = 0 ==> b = 3a. 
Along these lines, the last condition yields 3a + 6a + c = 0 ==> c = - 9a. 
Consequently, we have from the initial two conditions: 
- 27a + 9(3a) - 3(- 9a) + d = 3 ==> 27a + d = 3 
a + 3a - 9a + d = 0 ==> d = 5a. 
Along these lines, a = 3/32 and d = 15/32. 
==> b = 9/32 and c = - 27/32. 
That is, f(x) = (1/32)(3x^3 + 9x^2 - 27x + 15).
8 0
3 years ago
What is the range of the function y=\cos 2x ?
sattari [20]
All real numbers is the answer
7 0
3 years ago
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