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alexandr1967 [171]
3 years ago
5

F(n)=2n+4 g(n) = 4n - 2 Find f (g(2))

Mathematics
1 answer:
ivolga24 [154]3 years ago
8 0

Answer: f(g(2))=16

Step-by-step explanation:

Given the function f(n):

f(n)=2n+4

And the function g(n):

g(n) = 4n - 2

The first step we can apply is to find g(2). To do it, we need to substitute n=2 into the function and then we must evalute. Then, this is:

g(2) = 4(2) - 2\\\\g(2) =8 - 2\\\\g(2)= 6

Finally, in order to find f (g(2)) we need to substitute g(2) found above, into the function f(n) and then we must evaluate.

So, we get:

f(g(2))=2(6)+4\\\\f(g(2))=12+4\\\\f(g(2))=16

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Find an equation of the slant asymptote. Do not sketch the curve. y = 5x4 + x2 + x x3 − x2 + 5
murzikaleks [220]

Answer:

The slant asymptote is y=5 x + 5.

Step-by-step explanation:

Line y=mx+b is a slant asymptote of the function y=f{\left(x \right)}, if either m=\lim_{x \to \infty}\left(\frac{f{\left(x \right)}}{x}\right)=L or m=\lim_{x \to -\infty}\left(\frac{f{\left(x \right)}}{x}\right)=L, and L is finite.

We want to find the slant asymptotes of the function

f(x)=\frac{5 x^{4} + x^{2} + x}{x^{3} - x^{2} + 5}

First, do polynomial long division

\frac{5 x^{4} + x^{2} + x}{x^{3} - x^{2} + 5}=5 x + 5+\frac{6 x^{2} - 24 x - 25}{x^{3} - x^{2} + 5}

Next, we use the above definition,

The first limit is

\lim_{x \to \infty}\left(\frac{6x^2-24x-25}{x^3-x^2+5}\right)=0

The second limit is

\lim_{x \to -\infty}\left(\frac{6x^2-24x-25}{x^3-x^2+5}\right)=0

The rational term approaches 0 as the variable approaches infinity.

Thus, the slant asymptote is y=5 x + 5.

8 0
3 years ago
The outside temperature was 4 degrees celsius. For the next 6 hours the temperaure canged at a mean rate of -0.8 degrees celsius
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The final temperature is 0
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3 years ago
Find the fifth term of the arithmetic sequence in which t1 = 3 and tn = tn-1 + 4. A) 5 B) 7 C) 19 D) 23 2) Find the tenth term o
Sergeu [11.5K]
We know that

Part a) <span>Find the fifth term of the arithmetic sequence in which t1 = 3 and tn = tn-1 + 4
t1=3
t2=t1+4----> 3+4-----> 7
t3=t2+4-----> 7+4----> 11
t4=t3+4-----> 11+4---> 15
t5=t4+4-----> 15+4---> 19

the answer Part a) is 19

Part b) </span><span>Find the tenth term of the arithmetic sequence in which t1 = 2 and t4 = -10

we know that 
tn=t1+(n-1)*d-----> d=[tn-t1]/(n-1)
t1=2
t4=-10
n=4
find the value of d
d=[-10-2]/(4-1)-----> d=-12/3----> d=-4
find the </span>tenth term (t10)
t10=t1+(10-1)*(-4)----> t10=2+9*(-4)----> t10=-34

the answer Part b) is -34

Part c) <span>Find the fifth term of the geometric sequence in which t1 = 3 and tn = 2tn-1
t1=3
t2=2*t1----> 2*3----> 6
t3=2*t2----> 2*6----> 12
t4=2*t3-----> 2*12---> 24
t2=2*t4----> 2*24----> 48

the answer Part c) is 48</span>
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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