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alexandr1967 [171]
3 years ago
5

F(n)=2n+4 g(n) = 4n - 2 Find f (g(2))

Mathematics
1 answer:
ivolga24 [154]3 years ago
8 0

Answer: f(g(2))=16

Step-by-step explanation:

Given the function f(n):

f(n)=2n+4

And the function g(n):

g(n) = 4n - 2

The first step we can apply is to find g(2). To do it, we need to substitute n=2 into the function and then we must evalute. Then, this is:

g(2) = 4(2) - 2\\\\g(2) =8 - 2\\\\g(2)= 6

Finally, in order to find f (g(2)) we need to substitute g(2) found above, into the function f(n) and then we must evaluate.

So, we get:

f(g(2))=2(6)+4\\\\f(g(2))=12+4\\\\f(g(2))=16

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Answer:

After translation:

Translation: (x, y)  →  (x-6, y-8)

W'X'Y'Z' = W'(-10, 0), X'(-10, -8), Y'(-18, -4), Z'(-14, 8)

After dilation:

Dilation: (x, y)  →  (2x, 2y), centered at (0, 0)

W''X''Y''Z'' = W'' (-20, 0), X'' (-8, 0) , Y'' (-24, 8), Z'' (-16, 32)

Step-by-step explanation:

Given the vertices of the Quadrilateral WXYZ

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  • X(-4, 0)
  • Y(-12, 4)
  • Z(-8, 16)

As the rule of translation is given by

Translation: (x, y)  →  (x-6, y-8)

So, after the translation the vertices of Quadrilateral WXYZ will be translated as:

W(-4, 8)  →  (x-6, y-8) ⇒ (-4-6, 8-8) = W'(-10, 0)

X(-4, 0)  →  (x-6, y-8) ⇒ (-4-6, 0-8) = X'(-10, -8)

Y(-12, 4)  →  (x-6, y-8) ⇒ (-12-6, 4-8) = Y'(-18, -4)

Z(-8, 16)  →  (x-6, y-8) ⇒ (-8-6, 16-8) = Z'(-14, 8)

Therefore,

W'X'Y'Z' = W'(-10, 0), X'(-10, -8), Y'(-18, -4), Z'(-14, 8)

Next, the rule of dilation is given by

Dilation: (x, y)  →  (2x, 2y), centered at (0, 0)

W'(-10, 0)  →  (2x, 2y) ⇒ (2(-10), 2(0)) = W'' (-20, 0)  

X'(-4, 0)  →  (2x, 2y) ⇒ (2(-4), 2(0)) = X'' (-8, 0)

Y'(-12, 4)  →  (2x, 2y) ⇒ (2(-12), 2(4)) = Y'' (-24, 8)

Z'(-8, 16)  →  (2x, 2y) ⇒ (2(-8), 2(16)) = Z'' (-16, 32)

Therefore,

W''X''Y''Z'' = W'' (-20, 0), X'' (-8, 0) , Y'' (-24, 8), Z'' (-16, 32)

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