1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yulyashka [42]
3 years ago
13

Elena is making greeting cards, which she will sell by the box at an arts fair. She paid $54 for

Mathematics
1 answer:
TiliK225 [7]3 years ago
7 0

Answer:

Elena's sales and expenses will both be $

396

if she sells

36

boxes of cards.

Step-by-step explanation:

You might be interested in
Write the expression -3x 2 + 2y 2 + 5xy - 2y + 5x 2 - 3y 2 in simplest form. Then, answer the following questions using complete
Nataliya [291]
2x2 + 5xy - 3y
there are three terms in the simplified expression
there is one negative term in the simplified expression
8 0
3 years ago
How many hours is 6:30am to 1:50pm
horrorfan [7]
7 Hours & 20 Minutes
8 0
3 years ago
Read 2 more answers
Angel's Door Dash order was $28.00.
grin007 [14]

Answer: 23.80

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What is the equation of the line that passes through the point (8,1) and has a slope of 3/4
iris [78.8K]

Answer:

believe the answer is

y =  \frac{3}{4} x - 5

Step-by-step explanation:

Hope this helps!

3 0
3 years ago
Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt
tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

f(x)= \sqrt{\dfrac{x+1}{x-1}}

g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

\dfrac{x+1}{x-1}>0

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

x+1\leq 0\Rightarrow x\leq -1

x-1\leq 0\Rightarrow x\leq 1

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0
3 years ago
Other questions:
  • Complete the solution of the equation. find the value of y when x equals -1. 8x - 2y= 10
    5·2 answers
  • This question please
    8·1 answer
  • Suppose the mean GPA of all students graduating from a particular university in 1975 was 2.40. The registrar plans to look at re
    9·1 answer
  • If james has 2 pieces of candy and gives 2 away but john gives him 2 more how much candy does james have?
    15·2 answers
  • look at pic 10 pts will mark brainilest
    15·1 answer
  • I NEED HELP!!!!!!!!!!!
    11·1 answer
  • What is the distance???
    14·2 answers
  • 51=3k<br><br>but what is k?<br><br>tysm for everyone helping me:)
    6·1 answer
  • The width of Hudson's science fair poster needs to be more than 2.5 feet wide. Which of the following shows what the width could
    5·1 answer
  • How do you find 2/3 of a number?.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!