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3 years ago

Which molecules is converted directly to acetyl CoA without the intermediate step of being converted first to pyruvate

Chemistry

1 answer:

Hitman42 [59]3 years ago

6 0

Answer:

Fatty acids

Explanation:

Acetyl coA is a compound vital for the process of cellular respiration in the mitochondria. It is the starting material of the kreb's cycle or TCA cycle, which takes place in the mitochondria. During the metabolism of glucose (glycolysis), a molecule called PYRUVATE is first synthesized before becoming acetyl coA in the mitochondrion.

However, the metabolism of FATTY ACIDS (monomers of lipids) directly gives rise to acetyl coA without first becoming pyruvate. The fatty acids molecule undergo Beta- oxidation to produce acetyl coA, which enters the TCA cycle to continue cellular respiration.

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the nucleus

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What name is given to a fuel made from living organisms (such as wood) or their waste?

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4 years ago

Write a balanced half-reaction for the reduction of gaseous oxygen to aqueous hydrogen peroxide in basic aqueous solution. Be su

Vesna [10]

Answer:

Balanced half-reaction: $O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)$

Explanation:

Balanced half-reaction for the reduction of gaseous oxygen to aqueous hydrogen peroxide in basic solution should be written in the following step-by-step manner:

Half-reaction: $O_{2}(g)\rightarrow H_{2}O_{2}(aq.)$

Balance H and O in basic medium: $O_{2}(g)+2H_{2}O(l)\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)$

Balance charge: $O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)$

Balanced half-reaction: $O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)$

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4 years ago

For the following reaction, the equilibrium constant Kc is 2.0 at a certain temperature. The reaction is endothermic. What do yo

jeyben [28]

Answer:

The correct answer is : 'the concatenation of NO will increase'.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

If the temperature is increased, so according to the Le-Chatlier's principle , the equilibrium will shift in the direction where increase in temperature occurs.

$2NOBr(g)\rightleftharpoons 2NO(g) + Br_2(g)$

As, this is an endothermic reaction, increasing temperature will add more heat to the system which move equilibrium in the forward reaction with decrease in temperature. Hence, the equilibrium will shift in the right direction.

So, the concatenation of NO will increase.

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4 years ago

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Explanation:

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3 years ago