The length of a rectangle exceeds the breadth by 8 cm. Find the area of the rectangle, if its perimeter is 180 cm
1 answer:
Answer:
2009cm^2
Step-by-step explanation:
Given data
let the length be L
and the width be w
so
w= x
L=x+8
P= 180cm
P= 2L+2W
180= 2(x+8)+2(x)
180= 2x+16+2x
collect like terms
180= 4x+16
180-16= 4x
164= 4x
x= 164/4
x=41
W= 41cm
L= 41+8
L= 49cm
A= L*W
A=49*41
A=2009cm^2
Hence the area is 2009cm^2
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Yk what all above you can’t go wrong with choosing all of the em tbh cuz u would get one of them righ
Answer:-2
Step-by-step explanation:
No solutions beacause you have to factor out numbers for -9 but they must equal -8 when adding them.
X=small bag
y=large bag
5x+3y=260
4x+2y=200
(5x+3y=260)*4 =20x+12y=1040
(4x+2y=200)*5 =20x+10y=1000
subtract two equations: 2y=40
divide: y=20
plug y in 5x+3*20=260
simplify x=40
small bag=$40
large bag=$20
