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yKpoI14uk [10]
2 years ago
15

The length of a rectangle exceeds the breadth by 8 cm. Find the area of the rectangle, if its perimeter is 180 cm

Mathematics
1 answer:
sergiy2304 [10]2 years ago
3 0

Answer:

2009cm^2

Step-by-step explanation:

Given data

let the length be L

and the width be w

so

w= x

L=x+8

P= 180cm

P= 2L+2W

180= 2(x+8)+2(x)

180= 2x+16+2x

collect like terms

180= 4x+16

180-16= 4x

164= 4x

x= 164/4

x=41

W= 41cm

L= 41+8

L= 49cm

A= L*W

A=49*41

A=2009cm^2

Hence the area is 2009cm^2

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san4es73 [151]

Answer:

  1. 625,000 J

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Step-by-step explanation:

You should be aware that the SI derived units of Joules are equivalent to kg·m²/s².

To reduce confusion between <em>m</em> for mass and m for meters, we'll use an <em>italic m</em> for mass.

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4. KE = (1/2)<em>m</em>v²

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2 years ago
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That would be written as:

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And the step-by-step equation would be:

z^{2} = 1 → we take the 2 to the right side of the equation and do the IO*

z = \sqrt{1} →we solve for \sqrt{1}

z = 1 → final answer


*Ps - IO is not an existing term and stands for inverse operation. In this case, because when we take to 2 to the right side of the equation (the 2 is a power) it'll have to turn into a square root (because exponents and roots are inverse operations)



Hope it helped,



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