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Gnom [1K]
3 years ago
9

X 1 2 3 4 y 5 10 15 20 What's the constant?

Mathematics
1 answer:
DiKsa [7]3 years ago
3 0

<u>Answer:</u>

x ---> 1

y ---> 5

<u>Step-by-step explanation:</u>

We are given paired values for two variables x and y and we are to determine the constant number by which each term is increased such that they are in a proportional relationship.

For x, we have the following paired values:

x: 1, 2, 3, 4

So here the difference between each consecutive term is 1 so the constant is 1.

And for y, we have:

y: 5, 10, 15, 20

In this case, the difference between each consecutive term is 5 so the constant is 5.

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An athletic stadium has a capacity of 1.5 × 10^4 fans. If 9 × 10^3 fans buy advance tickets to an event at the stadium, how many
Oduvanchick [21]
1.5 x 10^4 = 15,000
9 x 10^3 = 9,000

15,000 - 9,000 = 6,000 <=== or 6 x 10^3
8 0
4 years ago
Read 2 more answers
F(x) = x² + 3<br> Find f(-2)
Svetradugi [14.3K]

Answer:

7

Step-by-step explanation:

f(-2)=(-2)^2+3=4+3=7

6 0
2 years ago
Write an equation that models the given information: (-3, 4), (-2, 20), (-1, 100), (0, 500), (1, 2500), (2, 12500)
Lorico [155]

Answer:

3,4

Step-by-step explanation:

3,4

8 0
3 years ago
The difference between half a number and 11 is -25
kenny6666 [7]

Answer:

1/2n - 11 = -25

Hope this helps you! Have a good night!

Also, n = -28

1/2n - 11 = -25

1/2n - 11 + 11 = -25 + 11

1/2n = -14

1/2n / 1/2 = -14 / 1/2

n = -28

Check:

1/2(-28) - 11 = -25

-14 - 11 = -25

-25 = -25


6 0
3 years ago
Only problem 6a. Can someone demonstrate how to do this so I can do the rest solo?
Lisa [10]

as far as I can tell, is simply asking to write two more expressions, that are equivalent to the provided one, namely, grab the provided one and expand it, if you simplify the expanded version, you'd end up with the provided, for example

\bf \boxed{6a.1}~\hfill  \stackrel{changing}{\cfrac{29\cdot 3}{30\cdot 3}}\implies \stackrel{one}{\cfrac{87}{90}}~\hfill  \stackrel{changing}{\cfrac{29\cdot 7}{30\cdot 7}}\implies \stackrel{t wo}{\cfrac{203}{210}}\\\\\\\boxed{6a.3}~\hfill \stackrel{ch anging}{\cfrac{15\div 3}{30\div 3}}\implies \stackrel{one}{\cfrac{5}{10}}~\hfill \stackrel{changing}{\cfrac{15\div 5}{30\div 5}}\implies \stackrel{two}{\cfrac{3}{6}}

so let's do 6a1, 6a3 and 6a5.

\bf \boxed{6a.1}~\hfill \stackrel{changing}{\cfrac{29\cdot 3}{30\cdot 3}}\implies \stackrel{one}{\cfrac{87}{90}}~\hfill \stackrel{changing}{\cfrac{29\cdot 7}{30\cdot 7}}\implies \stackrel{t wo}{\cfrac{203}{210}} \\\\\\ \boxed{6a.3}~\hfill \stackrel{changing}{\cfrac{15\div 3}{30\div 3}}\implies \stackrel{one}{\cfrac{5}{10}}~\hfill \stackrel{changing}{\cfrac{15\div 5}{30\div 5}}\implies \stackrel{two}{\cfrac{3}{6}}

\bf \boxed{6a.5}~\hfill \stackrel{changing}{(9\cdot 10)\div (2\cdot 10)}\implies \stackrel{one}{90\div 20}~\hfill \stackrel{changing}{(9\cdot 70)\div(2\cdot 70)}\implies \stackrel{two}{630\div 140}

3 0
3 years ago
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