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3 years ago

9

X 1 2 3 4 y 5 10 15 20 What's the constant?

1 answer:

DiKsa [7]3 years ago

3 0

<u>Answer:</u>

x ---> 1

y ---> 5

<u>Step-by-step explanation:</u>

We are given paired values for two variables x and y and we are to determine the constant number by which each term is increased such that they are in a proportional relationship.

For x, we have the following paired values:

$x: 1, 2, 3, 4$

So here the difference between each consecutive term is 1 so the constant is 1.

And for y, we have:

$y: 5, 10, 15, 20$

In this case, the difference between each consecutive term is 5 so the constant is 5.

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The table below shows 10 data values:

andrezito [222]

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Hope this helps !

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3 years ago

Serenity Spa charges $59 for a one hour massage. They charge $0.95 per minute for each additional minute over an hour. If

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Answer:

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A.

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B.

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3 years ago

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stiks02 [169]

Answer:

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Step-by-step explanation:

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3 years ago

The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.

Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=5$ , we get,

$V=\frac{4}{3} (3.14)(125)$

$V=\frac{1580}{3}$

$V=523.3333 \ in^3$

Rounding off to two decimal places, we have,

$V=523.33 \ in^3$

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = $\frac{3}{4} (5)=3.75$

Radius of the third sphere = $\frac{3.75}{2} =1.875$

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=1.875$ , we get,

$V=\frac{4}{3} (3.14)(1.875)^3$

$V=\frac{4}{3} (3.14)(6.59)$

$V=27.5901 \ in^3$

Rounding off to two decimal places, we have,

$V=27.59 \ in^3$

Thus, the volume of the third sphere is 27.59 in³

4 0

4 years ago

You pick a card, roll a die, and find the sum. How many different sums are possible?

svlad2 [7]

Answer:

6

Step-by-step explanation:

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3 years ago