Answer:
9.2
Step-by-step explanation:
Since it is a right triangle, you can use the Pythagorean theorem to find the third side which is the hypotenuse.
a^2 + b^2 = c^2
7^2 + 6^2 = c^2
49 + 36 = c^2
85 = c^2
9.219 = C
So, the answer rounded to the nearest tenth would be: 9.2
Number of +ve integers divisible by 2 less than or equal to 210=a=210/2=105
number of +ve integers divisible by 3 less than or equal to 210=b=210/3=70
number of +ve integers divisible by 7 less than or equal to 210=c=210/7=30
number of +ve integers divisible by 2&3 less than or equal to 210=d=210/6=35
number of +ve integer divisible by 2&7 less than or equal to 210=e=210/14=15
number of +ve integer divisible by 3&7 less than or equal to 210=e=210/21=10
number of +ve integer divisible by 2&7&3 less than or equal to 210=e=210/42=5
<span>number of positive integers not larger than 210 and divisible by 2, 3 or 7=105+70+30-(35+15+10)+5
=150
so numbers not divisible=total-150
=210-150
=</span>60
Answer:
∣∣−13∣∣=13
Step-by-step explanation:
calculatorsoup
B. cdb ....angle cdb is adjacent to angle adb because they have a common side (line db)
