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ivanzaharov [21]
3 years ago
14

In the first year of a 10,000 investment the interest rate was 6%. All earned interest remained invested for the second year, an

d the interest rate increased to 7%. What was the percent increase of the entire investment after two years?
Mathematics
1 answer:
Aleks04 [339]3 years ago
7 0

Answer:

13.4%

Step-by-step explanation:

First year:

$10,000*6% = $600

New balance = $10,600

Second Year:

$10,600*7% = $742

$10,600+ $742 = $11,342

Total Return:

Final Balance - Initial balance

$11,342 - $10,000 = $1,342

$10,000*x ÷ $1,342

x = $1,342/$10,000

x = 0.1342

0.134 = 13.4%

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The simplest radical form of the expression is \mathbf{40 ^{2/3}x^{{10}/{3}}y^2}.

<h3>What is the simplification of power indices?</h3>

When we have indices in the form \mathbf{ax^{2/3}}, we are going to find the cube root of the (ax)². This can be mathematically expressed as:

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