Answer:
M: (2,-2)
N: (1,2)
O: (2,-4)
P: (5, -2)
Step-by-step explanation:
What you would do is find out where the two lines intercross. The 2 right quadrants are positive. The two left are negative. Count the lines and figure out the ordered pair. X is left and right, y is up and down. For example, if you were given a ordered pair, (4,-2) you would go up four, and left 2.
Add 12 to both sides.
q-12 > 3
q > 15
ANSWER: q > 15
Answer:
Circular paraboloid
Step-by-step explanation:
Given ,

Here, these are the respective
axes components.
- <em>Component along x axis
</em>
- <em>Component along y axis
</em>
- <em>Component along z axis
</em>
We see that , from the parameterised equation , 
This can also be written as :

This is similar to an equation of a parabola in 1 Dimension.
By fixing the value of z=0,
<u><em>We get
which is equation of a parabola curving towards the positive infinity of y-axis and in the x-y plane.</em></u>
By fixing the value of x=0,
<u><em>We get
which is equation of a parabola curving towards positive infinity of y-axis and in the y-z plane. </em></u>
Thus by fixing the values of x and z alternatively , we get a <u>CIRCULAR PARABOLOID. </u>
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