Answer:
a−4b
Step-by-step explanation:
Combine Like Terms:
=4a+−6b+−3a+2b
=(4a+−3a)+(−6b+2b)
=a+−4b
have a great day
The answer to your question is 20
Answer:
Midpoint (-2,4)
distance nearest tenth = 8.9
The approximate distance = 9
Step-by-step explanation:
Formulas
PQ midpoint = (x2 + x1)/2, (y2 + y1)/2
distance d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )
Givens
x2 = -4
x1 = 0
y2 = 1
y1 = 7
Solution
M(PQ) = (-4+0)/2, (1 + 7)/2
M(PQ) = -2, 4
The midpoint is -2,4
The distance = sqrt( (4 - 0)^2 + (1 + 7)^2 )
The distance = sqrt(16 + 64)
The distance = sqrt(80)
The distance = 4√5 exactly
The distance = 8.94
The distance = 8.9 To the nearest tenth
Question 2
The distance is rounded to the nearest whole number which is 9.
Answer:
d.
Step-by-step explanation:
To convert a root to a fraction in the exponent, remember this rule:
![\sqrt[n]{a^{m}}=a^{\frac{m}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%7D%3Da%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D)
The index becomes the denominator in the fraction. (The index is the little number in front of the root, "n".) The original exponent remains in the numerator.
In this question, the index is 4.
The index is applied to every base in the equation under the root. The bases are 16, 'x' and 'y'.
![\sqrt[4]{16x^{15}y^{17}} = (\sqrt[4]{16})(\sqrt[4]{x^{15}})(\sqrt[4]{y^{17}}) = (2)(x^{\frac{15}{4}}})(y^{\frac{17}{4}}) = 2x^{\frac{15}{4}}}y^{\frac{17}{4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16x%5E%7B15%7Dy%5E%7B17%7D%7D%20%3D%20%28%5Csqrt%5B4%5D%7B16%7D%29%28%5Csqrt%5B4%5D%7Bx%5E%7B15%7D%7D%29%28%5Csqrt%5B4%5D%7By%5E%7B17%7D%7D%29%20%3D%20%282%29%28x%5E%7B%5Cfrac%7B15%7D%7B4%7D%7D%7D%29%28y%5E%7B%5Cfrac%7B17%7D%7B4%7D%7D%29%20%3D%202x%5E%7B%5Cfrac%7B15%7D%7B4%7D%7D%7Dy%5E%7B%5Cfrac%7B17%7D%7B4%7D%7D)
To find the quad root of 16, input this into your calculator. Since 2⁴ = 16,
= 2.
For the "x" and "y" bases, use the rule for converting roots to exponent fractions. The index, 4, becomes the denominator in each fraction.

Answer:
whichever way the opening of the sign points go the opposite. if it is less than or equal to, closed circle
Step-by-step explanation:
>
the line would point this way -->
sorry if this doesnt help