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3 years ago

How is solving equations different from solving inequalities?

Mathematics

1 answer:

Evgen [1.6K]3 years ago

7 0

Answer: Sometimes you may have to flip the sign on inequalities when your dividing or multiplying by a negative.

Step-by-step explanation:

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Why does (-4 1/2)^2 = 20.25? Thank you please hurry!

AnnZ [28]

Answer:

See below.

Step-by-step explanation:

Squaring a number means to multiply the number by itself.

For example, 3^2 means 3 * 3.

8^2 means 8 * 8.

(-6)^2 means (-6) * (-6).

In each case above, you see that the number that is squared is multiplied by itself.

In this case, (-4.5)^2, squaring the number -4.5, means multiply the number -4.5 by the number -4.5

(-4.5)^2 = (-4.5) * (-4.5)

Now we need to actually multiply -4.5 by -4.5

When you multiply a negative number by a negative number, the result is positive, so the product of -4.5 and -4.5 is a positive number. To find that number, you multiply 4.5 by 4.5

4.5 * 4.5 = 20.25

Therefore, (-4.5)^2 = 20.25

4 0

3 years ago

In another problem in my homework, it says look at problem 4, problem 4 has to do with the question about seans team when it had

notka56 [123]

I dont know because I’m confused

3 0

3 years ago

Solve each of the following equations for xx using the same technique as was used in the Opening Exercise.

aleksandrvk [35]

Answer:

The value of x is 3/2.

Step-by-step explanation:

Given data in the question:-

$3^2^x=27$

We have to find the value x.

Let $3^2^x=27$ be eq(i).

Solving eq (i)

$3^2^x=3^3$

using the properties of the exponents we have

if aⁿ=aˣ

then n=x

$2x=3\\x=3/2$

Hence the answer is 3/2.

4 0

3 years ago

The cost of an adult ticket to Jim's Jungle World is 3 times the cost of a child's ticket. Let a represent the cost of an adult

RSB [31]

That equation is
a=3c

5 0

2 years ago

What are the real zeroes of x3 + 6 x2 – 9x - 54?

o-na [289]

Answer:

Option B 3,-3,-6 is correct.

Step-by-step explanation:

We need to find real zeroes of $x^3+6x^2-9x-54$

Solving

$x^3+6x^2-9x-54\\=(x^3+6x^2)+(-9x-54)$

Taking x^2 common from first 2 terms and -9 from last two terms we get

$=(x^3+6x^2)+(-9x-54)\\=x^2(x+6)-9(x+6)\\$

Taking (x+6) common

$(x+6)(x^2-9)\\$

x^2-9 can be solved using formula a^2-b^2 = (a+b)(a-b)

$=(x+6)((x)^2-(3)^2)\\=(x+6)(x+3)(x-3)$

Putting it equal to zero,

$(x+6)(x+3)(x-3) =0\\x+6 =0, x+3=0\,\, and\,\, x-3=0\\x=-6, x=-3\,\, and\,\, x=3$

So, Option B 3,-3,-6 is correct.

7 0

2 years ago