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lidiya [134]
3 years ago
9

Help me plz. The sides of a rectangular terrain are given by the expressions (x - 5) y

Mathematics
1 answer:
tatyana61 [14]3 years ago
4 0

Area = (x - 5)(x – 7)

Area = x(x - 7) - 5(x - 7)

Area = x^2 -7x -5x + 35

Area = x^2 -12x + 35

algebraic expression that represents its area: x^2 -12x + 35

x^2 - 12x + 35 = 195

x^2 - 12x + 35 - 195 = 0

x^2 - 12x - 160 = 0

x^2 - 8x - 20x - 160 = 0

x (x + 8) - 20 (x + 8) = 0

(x + 8) (x - 20) = 0

(x + 8) = 0

(x - 20) = 0

x = - 8 (not a solution)

x = 20

hence,

length = x - 5

length = 20 - 5

length = 15 m

width = x - 7

width = 20 - 7

width = 13 m

perimeter = 2(13) + 2(15)

perimeter = 26 + 30

perimeter = 56 m²

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3 years ago
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Brilliant_brown [7]

Answer:

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3 years ago
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dexar [7]

A x = 0

using the law of exponents a^{0} = 1

for (6² )^ x = 1 then x = 0

B note that 6^{0} = 1 ⇒ x = 1

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6 0
3 years ago
(csc x - 1) (csc x + 1)
victus00 [196]
<h2>Explanation:</h2>

Here we have the following expression:

(csc x - 1) (csc x + 1)

So we need to extend this. Remember that the difference of squares tells us:

(a-b)(a+b)=a^2-b^2

So here:

a=cscx \\ \\ b=1

Thus:

(csc x - 1) (csc x + 1)=csc^2x-1 \\ \\ \\ But: \\ \\ cscx=\frac{1}{sinx} \\ \\ \\ Then: \\ \\ csc^2x-1=\frac{1}{sin^2x}-1=\frac{1-sin^2x}{sin^2x}=\frac{cos^2x}{sin^2x}=cot^2x \\ \\ \\ Finally: \\ \\ \boxed{(csc x - 1) (csc x + 1)=cot^2x}

4 0
3 years ago
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