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3 years ago

Help me plz. The sides of a rectangular terrain are given by the expressions (x - 5) y

Mathematics

1 answer:

tatyana61 [14]3 years ago

4 0

Area = (x - 5)(x – 7)

Area = x(x - 7) - 5(x - 7)

Area = x^2 -7x -5x + 35

Area = x^2 -12x + 35

algebraic expression that represents its area: x^2 -12x + 35

x^2 - 12x + 35 = 195

x^2 - 12x + 35 - 195 = 0

x^2 - 12x - 160 = 0

x^2 - 8x - 20x - 160 = 0

x (x + 8) - 20 (x + 8) = 0

(x + 8) (x - 20) = 0

(x + 8) = 0

(x - 20) = 0

x = - 8 (not a solution)

x = 20

hence,

length = x - 5

length = 20 - 5

length = 15 m

width = x - 7

width = 20 - 7

width = 13 m

perimeter = 2(13) + 2(15)

perimeter = 26 + 30

perimeter = 56 m²

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3 years ago

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

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Extreme value:

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Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

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So, we get equation as

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Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

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